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3 years ago

If a rocket-powered sled is accelerated to a speed of 440 m/s in 2.20 seconds, then what is the acceleration?

Physics

1 answer:

Margarita [4]3 years ago

3 0

Answer:

a = 200 m/s²

Explanation:

Given,

The initial speed of rocket-powered sled, u = 0

The final speed of rocket-powered sled, v = 440 m/s

Time taken to reach final speed, t = 2.20 s

The acceleration of the body is given by the change in velocity by time

a = (v - u) / t

= (440 - 0) / 2.20

= 200 m/s²

Therefore, the acceleration of the rocket-powered sled, a = 200 m/s²

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AfilCa [17]

Answer:

P.E. = -0.449 J

Explanation:

Potential energy of a charge particle in any electrostatic field is defined as the amount of work done ( in negative ) to bring that charge particle from any position to a new position r.

Now Potential energy is defined by this formula,

P.E. = k q₁ q₂/ r

where P.E. is the potential energy.

k = 1/( 4πε₀) = 8.99 × 10⁹ C²/ ( Nm²)

q₁ = charge of one particle = +1.0μC

q₂ = charge of another particle = -5.0μC

r = distance = 0.1 m

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3 years ago

On a velocity time graph, the slope tells you the ______ of the object.

Paraphin [41]

The acceleration is the correct answer

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3 years ago

In order to be _______________ forces, their effects must cancel each other out and not cause a change in the object's motion

Tju [1.3M]

Balancing.

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3 years ago

A girl throws a pebble into a deep well at 4.0 m/s (downward). It hits the water in 2.0 s. How far below the ground is the water

alexandr402 [8]

Answer:

27.6 m
13.8 m/s

Explanation:

(b) The initial velocity is added to that due to acceleration by gravity. The velocity is increased linearly by gravity at the rate of 9.8 m/s². The average velocity of the pebble will be its velocity halfway through the 2-second time period.* That is, it will be ...

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d = vt

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The water is about 27.6 m below ground.

_____

* We have chosen to make use of the fact that the velocity curve is linear, so the average velocity is half the sum of initial and final velocities:

vAvg = (vInit + vFinal)/2 = (vInit + (vInit +at))/2 = vInit +at/2

If you work this in a straightforward way, you would find distance as the integral of velocity, then find average velocity from the distance and time.

$\displaystyle d=\int_0^t{(v_0+at)}\,dt=v_0t+\dfrac{1}{2}at^2=t\left(v_0+a\dfrac{t}{2}\right)\\\\v_{avg}=\dfrac{d}{t}=v_0+a\dfrac{t}{2}\qquad\text{the formula we started with}$

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