The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.
Co = 10pd/M
Where;
Co = concentration = ?
p = percent of the hydrogen peroxide = 30%
d = Density of hydrogen peroxide = 1.39 g/ml
M = Molar mass = 34 g/mol
Substituting values;
Co = 10 × 30 × 1.39/34
Co = 12.26 M
The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.
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Answer:
The molar concentration of HCl in the aqueous solution is 0.0131 mol/dm3
Explanation:
To get the molar concentration of a solution we will use the formula:
<em>Molar concentration = mass of HCl/ molar mass of HCl</em>
<em></em>
Mass of HCl in the aqueous solution will be 40% of the total mass of the solution.
We can extract the mass of the solution from its density which is 1.2g/mL
We will further perform our analysis by considering only 1 ml of this aqueous solution.
The mass of the substance present in this solution is 1.2g.
<em>The mass of HCl Present is 40% of 1.2 = 0.48 g.</em>
The molar mass of HCl can be obtained from standard tables or by adding the masses of Hydrogen (1 g) and Chlorine (35.46 g) = 36.46g/mol
Therefore, the molar concentration of HCl in the aqueous solution is 0.48/36.46 = 0.0131 mol/dm3
Answer: D
Explanation: because of because
Answer:
no. of water molecules associated to each molecule of 
= 4
Explanation:
Mass of before heating = 19.8 g
Mass of after heating = 12.6 g
Difference in mass of before and after heating
= 19.8 - 12.6 = 7.2 g
Difference in mass corresponds to mass of water driven out.
Molar mass of water = 18 g/mol
No. of moles of water = 
Mass of obtained after heating is mass of anhydrous .
Mass of anhydrous = 12.6 g
Molar mass of = 125.9 g/mol
No. of mol of anhydrous = 
so,
0.1 mol of have 0.4 mol of water
1 mol of will have = 
Hence, no. of water molecules associated to each molecule of = 4
