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bogdanovich [222]
3 years ago
10

Matthew is looking at two different atoms. One has 8 protons and 10 neutrons. The other substance has 8 protons and 12 neutrons.

Are these the same element? Why or why not?
Physics
1 answer:
Lunna [17]3 years ago
6 0

Answer:

They are the same element.

Explanation:

Atom >>>>> Proton >>>> Neutron

A >>>>>>>> 8 >>>>>>>>> 10

B >>>>>>>> 8 >>>>>>>>> 12

From the table above we can see that both atoms have the same proton number.

Therefore, they are the same element because they have the same proton number which means that they have the same atomic number. The element in this case is existing as an isotope in that the atoms have the same proton number but different neutron number.

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What is an inelastic collision?
Radda [10]

Answer:

An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision. Both momentum and kinetic energy are conserved quantities inelastic collisions.

Explanation:

Suppose two similar trolleys are traveling toward each other with equal speed. They collide, bouncing off each other with no loss in speed. This collision is perfectly elastic because no energy has been lost.  In reality, examples of perfectly elastic collisions are not part of our everyday experience. Some collisions between atoms in gases are examples of perfectly elastic collisions. However, there are some examples of collisions in mechanics where the energy lost can be negligible. These collisions can be considered elastic, even though they are not perfectly elastic. Collisions of rigid billiard balls or the balls in Newton's cradle are two such examples.

7 0
3 years ago
Read 2 more answers
You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo
S_A_V [24]

Answer:

A.  Z = 185.87Ω

B.  I  =  0.16A

C.  V = 1mV

D.  VL = 68.8V

E.  Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

Z=\sqrt{R^2+\omega^2L^2}       (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

I=\frac{V}{Z}                     (2)

V: voltage amplitude = 30.0V

I=\frac{30.0V}{185.87\Omega}=0.16A

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV            (3)

D. The voltage across the inductor is:

V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V

E. The phase difference is given by:

\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°

5 0
3 years ago
Question #1: The visible part of the EM spectrum ranges from about 390 nanometers to about 720 nanometers. A nanometer (nm) is 1
mojhsa [17]

Answer:

The blue light has the highest energy.      

Explanation:

Body that is hot enough emits light as consequence of its temperature. For example, an iron bar in contact with fire will start to change colors as the temperature increases until it gets to a blue color. That its know as Wien's displacement law, which establishes that the peak of emission for the spectrum will be displaced to shorter wavelengths as the temperature increases.

The same scenario described above can be found in the star, a star with higher temperature will have a blue color and one with lower temperature will have a red color.

T = \frac{2.898x10^{-3} m. K}{\lambda max}  (1)

The energy of each wavelength can be determined by means of the following equation:

E = h\nu (2)

but \nu = \frac{c}{\lambda}, therefore:

E = \frac{hc}{\lambda}  (3)

     

Where h is the planck's constant and \nu is the frequency.

Notice that it is necessary to express the frequency in units of meters for a better representation of the energy.

\nu_{blue} = 400nm . \frac{1x10^{-9}m}{1nm} ⇒ 4x10^{-7}m

\nu_{red} = 720nm . \frac{1x10^{-9}m}{1nm} ⇒ 7.2x10^{-7}m

           

Case for the bluest light:

E = \frac{(6.626x10^{-34}J.s)(3x10^{8}m/s)}{4x10^{-7}m}                                                      

E = 4.96x10^{-19}J                                

                             

Case for the reddest light:    

     

E = \frac{(6.626x10^{-34}J.s)(3x10^{8}m/s)}{7.2x10^{-7}m}                                                        

     

E = 2.76x10^{-19}J                

                           

Equation 3 show that if the wavelength is lower the energy will be greater (inversely proportional).

Hence, according with the result and what was explained above, the blue light has the highest energy.

7 0
3 years ago
One isotope of a metallic element has the mass number 65 and 35 neutrons in the nucleus. the cation derived from the isotope has
Lina20 [59]
The mass number of an isotope is the sum of the numbers of protons and the numbers of the neutron. Given that the mass number is 65 and the number of neutrons is 35, the number of protons is 30. The atom is then Zinc (Zn). The charge is equal to +2, as it lacks 2 more electrons. 
7 0
4 years ago
Consider a single turn of a coil of wire that has radius 6.00 cm and carries the current I = 1.50 A . Estimate the magnetic flux
Fofino [41]

Answer:

a

  \phi = 1.78 *10^{-7} \  Weber

b

 L  = 1.183 *10^{-7} \  H

Explanation:

From the question we are told that

   The radius is  r = 6 \ cm =  \frac{6}{100} =  0.06 \ m

   The current it carries is  I  = 1.50 \ A

     

The  magnetic flux of the coil is mathematically represented as

       \phi = B  * A

Where  B is the  magnetic field which is mathematically represented as

         B  =  \frac{\mu_o  * I}{2 *  r}

Where  \mu_o is the magnetic field with a constant value  \mu_o  =  4\pi * 10^{-7} N/A^2

substituting  value

          B  =  \frac{4\pi * 10^{-7}   * 1.50 }{2 *  0.06}

          B  =  1.571 *10^{-5} \ T

The area A is mathematically evaluated as

       A  = \pi r ^2

substituting values

       A  = 3.142 *  (0.06)^2

       A  = 0.0113 m^2

the magnetic flux is mathematically evaluated as    

        \phi = 1.571 *10^{-5} * 0.0113

         \phi = 1.78 *10^{-7} \  Weber

The self-inductance is evaluated as

       L  =  \frac{\phi }{I}

substituting values

        L  =  \frac{1.78 *10^{-7} }{1.50 }

         L  = 1.183 *10^{-7} \  H

7 0
3 years ago
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