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RoseWind [281]
3 years ago
5

Determine the pH of a 0.188 M NH 3 solution at 25°C. The K b of NH 3 is 1.76 × 10 -5.

Chemistry
1 answer:
Archy [21]3 years ago
5 0

Answer:

pH is 8.52

Explanation:

According to the working in the photo

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I'm assuming false but really have no clue
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3 years ago
What is the hydrogen ion concentration of 0.450M solution of acetic acid (HC2H3O2), if the ionization constant(Ka) is 2.19 x 10-
WITCHER [35]

Answer:

3.02 Mm

Explanation:

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3 years ago
We gave an object with a density of 620 g/cm^3 and a volume of 75cm^3. What is the mass of this object?
Hitman42 [59]
d=\frac{m}{V} \ \ \ \Rightarrow \ \ m=dV\\\\
d=620\frac{g}{cm^{3}}\\
V=75cm^{3}\\\\\
m=620\frac{g}{cm^{3}}*75cm^{3}=46500g
6 0
4 years ago
The decomposition of N2O4 into NO2 has Kp = 2. Some N2O4 is placed into an empty container, and the partial pressure of NO2 at e
Sunny_sXe [5.5K]

Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

           N_{2}O_{4} \rightarrow 2NO_{2}

Let us assume that x concentration of N_{2}O_{4} is present at the initial stage. Therefore, according to the ICE table,

                    N_{2}O_{4} \rightarrow 2NO_{2}

Initial :               x                   0

Change :       - 0.1        2 \times 0.1

Equilibrium : (x - 0.1)             0.2

Now, expression for K_{p} of this reaction is as follows.

     K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

Putting the given values into the above formula as follows.

          K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

                 2 = \frac{(0.2)^{2}}{(x - 0.1)}

                2 \times (x - 0.1) = (0.2)^{2}

                            x = 0.12

This means that P_{N_{2}O_{4}} = x = 0.12 atm.

Thus, we can conclude that the initial pressure in the container prior to decomposition is 0.12 atm.

6 0
3 years ago
According to the below equation, how many moles of SO2 are required to generate 1.43×1024 water molecules?
podryga [215]
Make sure the equation is always balanced first. (It is balanced for this question already) 6.022 x 10^23 is Avogadro’s number. In one mole of anything there is always 6.022 x 10^23 molecules, formula units, atoms. For one mol of an element/ compound use molar mass (grams).

Multiply everything on the top = 8.61x10^47
Multiple everything on bottom= 1.20x10^24
Divide top and bottom = 7.15x10^23

Answer: 7.15x10^23 mol SO2
3 0
4 years ago
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