Answer:
so separation between slit is 0.12 mm
Explanation:
given data
slit wide = 0.020 mm
wavelength λ = 589.6 nm
fringe pattern n = 11
to find out
separation between the slits
solution
we know that for maxima we can say
d sinθ = m × λ .........1
and m is mth order maxima
and for central maxima
number of bright fringe is here
N = 2m -1
11 = 2m - 1
m = 6
so here number of maxima on either side of central maxima will be m-1
that is = 5
because we know 6th maxima will be minimized by minima
so
condition for minima is
a sin(θ) = n × λ
now for 1st minima
a sin(θ) = λ
and
= m
d = ma
d = 6 × 0.02
d = 0.12 mm
so separation between slit is 0.12 mm
Answer:
63N, 45N
Explanation:
Given:
Tension 1 = T1
We have the following free body equations:
F - T1 = 100*0.3 -(I)
T1 - T2 = 60*0.3 -(II)
T2 = 150*0.3 -(III)
Adding the three above equations, we have
F - T1 + T1 - T2 + T2 = (100*0.3) + (60*0.3) + (150*0.3)
Hence, F = 93N
Hence, substituting into equation I we have
T1 = Force by bar on lighter cart = 93 - (100*0.3) = 63N
Hence, force that heavier cart exerts on bar
T2 = 150*0.3 = 45N
Answer:
128 degrees
Explanation:
speed divided by distance travelled
A, because it specifies the number of people
Answer:
The acceleration of the ball is 200 m/s^2