Answer:
so the height will be increased by 9 times
Explanation:
The truck is in its pontential energy at rest
The potential energy is converted to kinetic energy when in motion
Given that,
h = height of the hill
m = mass of the truck
g = acceleration due to gravity
v = velocity of the truck at the bottom of the hill.
At the top of the hill,
Potential energy(PE) = mgh
Kinetic energy(KE) = 0
Total energy, E = PE + KE = mgh + 0 = mgh____(1)
At the bottom of the hill :
Potential energy, PE = 0
Kinetic energy,KE = (1/2)mv²
Total energy, E = PE + KE
= 0 + (1/2)mv²_____(2)
In law of conservation of energy,
(1) = (2)
mgh = (1/2)mv²
h = (1/2g)v²
given,
v = 2 m/s
g = 9.81 m/s²
h = (1/2(9.81)) × 2²
h = 0.20 m
so,
if v = 6 m/s
h = (1/2(9.81)) × 6²
h = 1.83 m
from the first h = 0.20m and the second h = 1.83m
1.83m / 0.20m
= 9.15
so the height will be increased by 9 times
