Answer:
P=1113.35 psi
Explanation:
For tank 1
V₁= 6.25 L
P₁=1759 psi
For tank 2
V₂=6.25 L
P₂=467.7 psi
Lets take final pressure is P
The final volume V= 6.25 + 6.25 L = 12.5 L
P V = V₂P₂+V₁P₁
Now by putting the values
P V = V₂P₂+V₁P₁
P x 12.5 = 6.25 x 467.7+6.25 x 1759
P=1113.35 psi
So the final volume of the system will be 1113.35 psi.
More massive attacking objects speed slows down and it transfer its some kinetic energy to less massive target objects whereas less massive target objects starts its motion
Answer:
Explanation:
a)8*7.2=57.6 cm^2
b)8*8=64 m^2
c)3.4*5.2=17.68 mm*2
d)2.6*4.7=12.22 m^2
e)13*5.1=13*5100=66300 m^2
Depends on how strong you are. People can hit it anywhere between a few inches and 500 yards.
force in component form is given as
F~ = Fx ˆı + Fy ˆj
given that : Fx = 4 N, Fy = −3 N
hence the force equation looks like
F~ = 4 ˆı + (- 3) ˆj
F~ = 4 ˆı - 3 ˆj
displacement is given as
~s = sx ˆı + sy ˆj
given that : sx = 1 m, and sy = 1 m
hence the displacement is given as
~s = 1 ˆı + 1 ˆj
work done is the dot product of force and displacement . hence work done is given as
W = F~.~s
W = (4 ˆı - 3 ˆj) . (1 ˆı + 1 ˆj )
W = (4 x 1) ( ˆı.ˆı) - (3 x 1) (ˆj.ˆj)
W = 4 - 3
W = 1 J
θ = angle between F~ and ~s = ?
hence the work done by the force comes out to be 1 J
|F~| = magnitude of force = sqrt(Fx² + Fy²) = sqrt((4)² + (-3)²) = 5 N
|~s| = magnitude of displacement = sqrt(sx² + sy²) = sqrt((1)² + (1)²) = sqrt(2)
we know that work done is given as
W = |F~| |~s| Cosθ
1 = (5) (sqrt(2) Cosθ
Cosθ = 0.142
θ = Cos⁻¹(0.142)
θ = 81.84 deg