Water vapor in the air is often referred to as?

Following are the different layers of the Sun's atmosphere. Rank them based on the order in which a probe would encounter them w

Ghella [55]

Answer:

Sequence of layers to encounter while travelling from Earth to the surface of the sun are:

Option (A) - Corona

Option (C) - Chromosphere

Option (B) - Photosphere

Explanation:

Corona- It represents the extreme outer region of the surface of the sun. It is normally not visible because of the light emitted from the sun. So it is difficult to be seen from the naked eye, but it can be seen during the time of total solar eclipse. The temperature in this region is about several million degrees.

Chromosphere- It is a layer that lies between the Corona and the Photosphere. This layer has a thickness of about 2000 kilometers and the temperature in this layer ranges from about 6000°C to 20,000°C.

Photosphere- This layer is the bright visible layer of the sun which is comprised of plasma and dark and cool sunspots, that forms on the sun due to the emerging of the magnetic field of the sun from its surface.

Thus, the correct sequences are mentioned above.

3 0

3 years ago

What do most scientists think causes Bovine Spongiform Encephalopathy (Mad Cow Disease)?

Marianna [84]

Most scientists believe that it is caused by an abnormal protein in brain tissue, called a prion, that can cause fatal disease when eaten.

8 0

3 years ago

Read 2 more answers

A thundercloud has an electric charge of 48.8 C near the top of the cloud and –41.7 C near the bottom of the cloud. The magnitud

IceJOKER [234]

Answer: 1.51 km

Explanation:

Coulomb's Law: The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.

Or, $\vec{F}=k \frac{Q_{1} Q_{2}}{r^{2}}$

Where Q1 and Q2 are magnitude of two charges and r is distance between them:

Given:

Q1 = Charge near top of cloud = 48.8 C

Q2 = Charge near the bottom of cloud = -41.7 C

Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N

k = 8.99 x 109Nm^2/C^2

So,

$\begin{aligned}&7.98 \times 10^{6}=\left(8.99 \times 10^{9} \mathrm{Nm}^{2} / \mathrm{C}^{2}\right) \frac{48.8 \mathrm{C} \times 41.7 \mathrm{C}}{\mathrm{r}^{2}} \\&r=\sqrt{\frac{1.8294 \times 10^{13}}{7.98 \times 10^{6}}}=1.514 \times 10^{3} \mathrm{~m}=1.51 \mathrm{~km}\end{aligned}$

Therefore, the separation between the two charges (r) = 1.51 km

3 0

2 years ago

You are wearing earbuds or headphones to listen to your music but your family members can hear it as well. They tell you that it

allsm [11]

If it’s loud enough for your family to hear it, it’s best you turn it down. It could cause permanent damage to your ear drums if it’s loud enough and you could start to lose your hearing. So if your family were to tell you to turn it down, you should probably just turn it down!

5 0

3 years ago

A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the w

Leto [7]

A) 140 degrees

First of all, we need to find the angular velocity of the Ferris wheel. We know that its period is

T = 32 s

So the angular velocity is

$\omega=\frac{2\pi}{T}=\frac{2\pi}{32 s}=0.20 rad/s$