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Sati [7]
4 years ago
5

Why does silicon in silicon dioxide bond with 4 oxygen atoms and not 2?

Chemistry
1 answer:
Elis [28]4 years ago
5 0

Answer:

Silicon does not form double bonds with oxygen, whereas carbon is capable of forming double bonds with oxygen. While the carbon dioxide molecular structure is linear, the silicon dioxide has an extended, different covalent structure.

Explanation:

If the sizes of the atoms of Silicon (Si) and Carbon (C) are compared to each other, the Si atoms are larger than carbon - which implies that the Si-O bonds will be longer than the C-O bonds. As a result, the p orbitals present on the Si and O atoms aren't very near to each other, in order to get together for the required overlap sideways which could have formed a stable pi bond. Hence, Silicon forms only single covalent bonds with Oxygen in silicon dioxide, in the form of a diamond structure with each Si atom being connected to its four neighbouring atoms through an O atom.

On the other hand, in the case of carbon dioxide, C is perfectly capable of forming double bonds with O. The different p orbitals are brought close together, resulting in a sideways overlap that leads to two pi bonds, twisted at a right angle to each other. As a result, the Carbon in carbon dioxide bonds with 2 oxygen atoms but not 4.

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What mass of silver chloride precipitate will be produced if 25 cm3 of 0.1M silver nitrate is added to excess sodium chloride so
ehidna [41]

We have 25cm^3 of 0.1mol AgNO3.

25cm^3 = 0.025L, so we have 0.025 x 0.1 = 0.0025mol AgNO3, so

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What mass of chromium would be produced from the reaction of 57.0 g of potassium with 199 g of chromium(II) bromide according to
fredd [130]

Answer:

Mass of Chromium produced = 37.91 grams

Explanation:

2K + CrBr₂  →  2KBr + Cr

2mole     1 mole                1 mole

mass of Potassium = 57.0 grams

molar mass of Potassium = 39.1 g/mol

no of moles of Potassium = 57.0 / 39.1 = 1.458 moles

mass of CrBr₂= 199 grams

molar mass of CrBr₂ = 211.8 gram/mole

no of moles of CrBr₂ = 199 / 211.8 = 0.939 mole

From chemical equation

1 mole of CrBr₂ = 2 moles of K

∴ 0.939 moles of CrBr₂ = ?

   ⇒ 0.939 x 2/1 = 1.878 moles of K

1.878 moles of K is needed, but there is 1.458 moles of K. So, Potassium is completed first during the reaction . Hence, Potassium is limiting reagent. and CrBr₂ is excess reagent .

From chemical equation

2 moles of K = 1 mole of Cr

∴ 1.458 moles of K = ?

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no of moles of Cr formed = 0.729 moles

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mass of one mole of Cr = 52.0 grams

mass of 0.729 moles of Cr = 52.0 x 0.729 = 37.908 grams

mass of Chromium produced = 37.91 grams

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