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motikmotik
4 years ago
6

When you are balancing chemical reactions ('equations'), what must you never touch?

Chemistry
2 answers:
timofeeve [1]4 years ago
8 0

You should never touch the subscripts, as that will change the composition. Hope I helped!

frozen [14]4 years ago
6 0

<u>Answer:</u>

The correct answer option is: the number in subscript.

<u>Explanation:</u>

When you are balancing any chemical equation, you must never touch or change the number in subscript of the molecule of a chemical or compound.

The number in subscript of any molecule or compound shows the ratio of atoms that makes up that certain molecule or compound.

You can only change or alter the number written left to the molecule of compound to balance the equation.

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Which is the correct set of products for the acid-base neutralization reaction between hydrochloric acid and sodium hydroxide?
nydimaria [60]

Answer: I think the answer is C. NaCl and H2O

Explanation: I’m not sure tho

3 0
2 years ago
If all of the energy from burning 281.0 g of propane (ΔHcomb,C3H8 = –2220 kJ/mol) is used to heat water, how many liters of wate
lapo4ka [179]

This problem is providing us with the mass of propane, its enthalpy of combustion, and the initial and final temperature of water that can be heated from the burning of this fuel. At the end, the result turns out to be 42.27 L.

<h3>Combustion:</h3>

In chemistry, combustion reactions are based on the burning of fuels by using oxygen and producing both carbon dioxide and water. For propane, we will have:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

Hence, we can calculate the heat released from this reaction by using the mass, which has to be converted to moles, and the given enthalpy of combustion:

Q=281.0g*\frac{1mol}{44.09g}*-2220\frac{kJ}{mol}*\frac{1000J}{1kJ}\\ \\ Q=-1.415x10^7 J

<h3>Calorimetry:</h3>

In chemistry, we can analyze the mass-specific heat-temperature-heat relationship via the most general heat equation:

Q=mC\Delta T

Thus, since Q was obtained from the previous problem, but the sign change because the released heat is now absorbed by the water, one can calculate the mass of water that rises from 20.0°C to 100.0°C with this heat:

m=\frac{Q}{C\Delta T} =\frac{1.415x10^7J}{4.184\frac{J}{g\°C}(100.0\°C-20.0\°C)}\\ \\m=4.227x10^4g

Finally, we convert it to liters as required:

V=4.227 x10^4g*\frac{1mL}{1.00g}*\frac{1L}{1000mL}  \\\\V=42.27L

Learn more about calorimetry: brainly.com/question/1407669

4 0
2 years ago
. Using at least 3 to 4 complete content related sentences, explain how the compressed gas in an aerosol can forces paint out of
Sophie [7]
Erosols aren't aerosols at all. No, really, let's be clear about this. An aerosol is really the cloud<span> of </span>liquid and gas<span>that comes out of an aerosol can, not the can itself. In  fact, to be strictly correct about it, an aerosol is a fine mist of liquid, or lots of solid particles, widely and evenly dispersed throughout a gas. So clouds, fog, and steam from your kettle are all examples of aerosols, because they're made up of </span>water<span> droplets dispersed through a much bigger volume of air. Smoke is an aerosol too, though unlike those other examples (which are liquids dispersed in gases) it's made up of </span>solid<span> particles of unburned carbon mixed through a cloud of warm, rising air. Even </span>candles<span> make aerosols: the smoky steam swirling above a candle flame consists of soot and water vapor dispersed through hot air.

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3 0
4 years ago
Read 2 more answers
How many moles of bromine (Br) atoms are in a sample of 2.03 × 1024 atoms?
andriy [413]

The mole is simply an Avogadros number of anything( in this case Br atoms)

The Avogadro number is 6.022 x 10^23.

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3 0
4 years ago
Read 2 more answers
Predict the product(s) of the following reaction. (Separate substances in a list with a comma. Include states-of-matter under th
kiruha [24]

Answer:

Cu₃(PO₄)₂(s), RbNO₃(aq)

Explanation:

This reaction looks like a possible <em>double replacement reaction</em>, in which the metal ions have exchanged partners.

3Cu(NO₃)₂(aq) + 2Rb₃PO₄(aq) ⟶ Cu₃(PO₄)₂ + 6RbNO₃

You must recall the pertinent <em>solubility rules</em>:

1. Salts of Group 1 elements (e.g., Rb⁺) are soluble.

2. Salts containing nitrate ions (NO₃⁻) are soluble.

3. Most salts containing phosphate ions (PO₄³⁻) are insoluble

According to Rules 1 and 1, RbNO₃ is soluble.

According to Rule 3, Cu₃(PO₄)₂ is insoluble.

∴ 3Cu(NO₃)₂(aq) + 2Rb₃PO₄(aq) ⟶ Cu₃(PO₄)₂(s) + 6RbNO₃(aq)

6 0
4 years ago
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