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vichka [17]
3 years ago
7

Just pretend that the cases are numbered 1-5

Physics
1 answer:
Sliva [168]3 years ago
7 0

Answer:

Yes,

NO,

Yes,

Yes,

No.

Explanation:

CASE: A wire is moved through the field of a magnet

As the wire is moved through the field of a magnetic the magnetic flux through the circuit loop changes,; therefore current is induced.

CASE: A magnet is held close to a wire

There needs to be relative motion between the wire and the magnet for the current to be induced; therefore, simply holding a magnet close to a wire will not induce current in the circuit.

CASE: A magnet is moved into a coil of wire

As the magnet is moved into a coil of wire, the magnetic flux through the coil changes, and therefore, the current is induced.

CASE: A magnet is moved out of  coil of wire

Moving a magnet out of  coil of wire also changes the magnetic flux through the coil; therefore, the current is induced.

CASE: A magnet rests in coil of wire

There needs to be relative motion between the coil of wire and the magnet for the current to be induced; therefore, a magnet resting in the coil of wire will no induce any current in the coil.

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I need help with this question it’s potential energy and kinetic energy
yKpoI14uk [10]

Answer:

A bowling ball sitting on the rack: Potential

Sitting in the top of a tree: Potential

The chemical bonds in sugar: Potential

An archer with his bow drawn: Potential

A baseball thrown to second base: Kinetic

The wind blowing through your hair: Kinetic

A volleyball player spiking a ball: Kinetic

A bicyclist pedaling up a hill : Kinetic

A bowling ball rolling down the alley: Kinetic

Walking down the street: Kinetic

8 0
3 years ago
In a Little League baseball game, the 145 g ball reaches the batter with a speed of 15.0 m/s. The batter hits the ball, and it l
Oduvanchick [21]

Answer: 5.075Ns

Explanation:

Given the following :

Mass of ball = 145g

Initial Speed of ball = 15m/s

Final speed of ball when hit by the batter = - 20m/s ( Opposite direction)

The impulse of a body is represented using the relation:

Force(f) * time(t) = mass (m) * (final Velocity(V) - initial velocity(u))

Therefore, using:

m(v - u) = impulse

Mass of ball = 145 / 1000 = 0.145kg

Impulse = 0.145(- 20 - 15)

Impulse = 0.145(-35)

Impulse = 5.075Ns

3 0
3 years ago
The following are secondary sources of energy except a.coal b crude oil c nuclear d wind e wood
monitta

Answer:

d) Wind

Explanation:

Secondary energy is energy produced by converting energy available in its natural state in the environment. Hence Wind is a primary source not a secondary source

8 0
2 years ago
A 4.0-kg object moving at 3.0 m/s experiences a 16.0-Newton resistive force over a duration
sveta [45]

Answer:

D is the answer hope you it helps you

7 0
3 years ago
Three guns are aimed at the center of a circle, and each fires a bullet simultaneously. The directions in which they fire are 12
ikadub [295]

Answer:

The unknown mass of the bullet is  m1=3.751x10^{-3} kg

Explanation:

According to Newton's laws of motion, when a net external force acts on a body of mass  <u><em>m</em></u> , it results in change in momentum of the body and is given by:

F=\frac{P}{dt}

Where:

P

is the linear momentum of the body

As a consequence, when there are no external forces acting on the body the total momentum remains conserved i.e.

Given:

m_{2}=5.79x10^{-3}kg  \\m_{3}=5.79x10^{-3}kg\\v_{2}=v_{3}=392 \frac{m}{s}\\

For momentum along the y-direction to be zero, it is achieved when the equal masses are moving at angles of  

θ1=180°, θ2=60°, θ3=-60°

Therefore, from conservation of momentum along x - direction:

m_{1}*v_{1}*cos(180)+m_{2}*v_{2}*cos(60)+m_{3}*v_{3}*cos(-60)=0\\m_{1}*605\frac{m}{s}*cos(180)+5.79x10^{-3}kg *392\frac{m}{s}*cos(60)+5.79x10^{-3}kg*392\frac{m}{s}*cos(-60)=0\\

-m_{1}*605+5.79x10^{-3}kg*196\frac{m}{s}+5.79x10^{-3}kg*196\frac{m}{s}=0\\m_{1}*605kg= 2.26968\frac{kg*m}{s}\\m_{1}=3.75 x10^{-3} kg

3 0
3 years ago
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