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3 years ago

Just pretend that the cases are numbered 1-5

Physics

1 answer:

Sliva [168]3 years ago

7 0

Answer:

Yes,

NO,

Yes,

No.

Explanation:

CASE: A wire is moved through the field of a magnet

As the wire is moved through the field of a magnetic the magnetic flux through the circuit loop changes,; therefore current is induced.

CASE: A magnet is held close to a wire

There needs to be relative motion between the wire and the magnet for the current to be induced; therefore, simply holding a magnet close to a wire will not induce current in the circuit.

CASE: A magnet is moved into a coil of wire

As the magnet is moved into a coil of wire, the magnetic flux through the coil changes, and therefore, the current is induced.

CASE: A magnet is moved out of coil of wire

Moving a magnet out of coil of wire also changes the magnetic flux through the coil; therefore, the current is induced.

CASE: A magnet rests in coil of wire

There needs to be relative motion between the coil of wire and the magnet for the current to be induced; therefore, a magnet resting in the coil of wire will no induce any current in the coil.

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Answer:

Explanation:

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divide 1 and 2 we get

$\frac{1}{1}=\frac{2v_1t_1}{v_2t_2+v_3t_3}$

$\frac{t_1}{t_2}=\frac{v_2+v_3}{2v_1}$

Now average velocity is given by

$v_{avg}=\frac{d}{t_1+t_2}$

taking $t_1$ common

$v_{avg}=\frac{2v_1t_1}{t_1(1+\frac{t_2}{t_1})}$

$v_{avg}=\frac{2v_1}{1+\frac{2v_1}{v_2+v_3}}$

$v_{avg}=\frac{2v_1(v_2+v_3)}{2v_1+v_2+v_3}$

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3 years ago

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3 years ago

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Explanation:

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A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/

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Complete Question

A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/h, 18.0 min at 80.0 km/h, and 60.0 min at 60.0 km/h and spends

25.0 min eating lunch and buying gas

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Answer:

The value is $D = 139.02 \ km$