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shusha [124]
3 years ago
12

If an object placed in a fluid experiences a buoyant force equal to the weight of the fluid it displaces, the object will float.

Physics
1 answer:
enyata [817]3 years ago
6 0

Answer: The answer is False

Explanation: This is for the one's in apex <>

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When a person is exhibiting suppression, the forgetting that takes place is
Paraphin [41]

Answer:

C. due to memory decay.

Explanation:

3 0
2 years ago
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An object of mass 2kg raised to a height 10m possess potential energy of 200J. What is the kinetic energy and potential energy a
Shtirlitz [24]

Explanation:

{\bold{\sf{\underline{Understanding \: the \: concept}}}}

✠ This question says that there is an object and its mass is 2 kg ; it's raised to a height 10 m and possess potential energy of 200 J. Now this question ask us to find the kinetic energy and the potential energy at a height 4 metre.

\bold{↬{   }}{\bold{\sf{\underline{Given \: that}}}}

✰ Mass = 2 kilograms

✰ Raised height = 10 metres

✰ Posses potential energy = 200 Joules

\bold{↬{   }}{\bold{\sf{\underline{To \: find}}}}

✰ Kinetic energy at a height 4 metre

✰ Potential energy at a height 4 metre

{\bold{\sf{\underline{Solution}}}}

✰ Kinetic energy at a height 4 metre = 120 J

✰ Potential energy at a height 4 metre = 80 J

{\bold{\sf{\underline{Using \: concepts}}}}

✰ Potential energy formula.

{\bold{\sf{\underline{Using \: formula}}}}

✰ Potential energy = mgh

{\bold{\sf{\underline{We \: also \: write \: these \: as}}}}

✰ Potential energy as P.E

✰ Mass as m

✰ Joules as J

✰ Height as h

✰ Raised height as g

{\bold{\sf{\underline{Full \: solution}}}}

<h3>✠ Let us find the Potential energy.</h3>

↦ Potential energy = mgh

↦ Potential energy = 2 × 10 × 4

↦ Potential energy = 20 × 4

↦ Potential energy = 80 J

<h3>✠ Now according to the question let us find the kinetic energy</h3>

↦ Kinetic energy = Posses potential energy - Finded potential energy

↦ Kinetic energy = 200 J - 80 J

↦ Kinetic energy = 120 Joules

4 0
3 years ago
Read 2 more answers
A copper cylinder is initially at 21.1 ∘C . At what temperature will its volume be 0.163 % larger than it is at 21.1 ∘C?
fomenos

To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as V_1, the relation with the final volume as

V_2 = V_1 +0.163\% V_1

V_2 = V_1 +0.00163V_1

V_2 = 1.00163V_1

Initial temperature = 21.1\°C

Let T be the temperature after expanding by the formula of volume expansion

we have,

V_2 = V_1 (1+\gamma \Delta t)

Where \gamma is the volume coefficient of copper 5.1*10^{-5}/C

1.00163V_1 = V_1(1+\gamma(T-21.1\°))

1.00163 = 1+5.1*10^{-5}(T-21.1\°)

0.00163 = 0.000051T-0.0010761

T = 53.0608\°C

Therefore the temperature is 53.06°C

7 0
3 years ago
A ball is dropped from a tall bridge of height 48 m. What will the speed of the ball be immediately before it hits the ground, i
soldi70 [24.7K]

Answer:

2700

Explanation:

because calculate the minute1=60×45=2700

5 0
3 years ago
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Find the y-component of this
Alborosie

Answer:

-0.0789 m

Explanation:

Recall that the y-component comes associated with the sin(18.4) through the following trigonometric relationship:

y = 0.250 sin(-18.4) ≈ -0.0789 m

Notice it is negative since it is below the x-axis.

4 0
3 years ago
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