i dont get it so much but
The weight of the bag pack is 8.2 N. g = 1.64 m/s2. Hence, the acceleration due to gravity on moon is 1.64 m/s2. sooo? is it right
Huh? Wheres the question at?
Answer:
58.32 N
Explanation:
Area of a circle = 

where r is the radius of the circle.
The cylinder has a radius of 0.02 m, its area is;
= 

=
x 
=
x 0.0004
= 1.2571 x 
Area of the cylinder is 0.0013
.
The safety valve has a radius of 0.0075 m, its area is;
= 

=
x 
=
x 5.625 x 
= 1.7679 x 
Area of the valve is 0.00018
.
From Hooke's law, the force on the safety valve can be determined by;
F = ke
= 950 x 0.0085
= 8.075 N
Minimum force,
, required can be determined by;
= 
= 
= 
= 58.32
The minimum force that must be exerted on the piston is 58.32 N.
The Coulomb's law equation is F = Kq₁q₂/r².
<h3>
What is Coulomb's law?</h3>
This is the law that relates the product of two charges to the square of distance between the two charges.
Coulomb's law states that the force of attraction or repulsion is directly proportional to the product of the charges and inversely proportional to the square of distance between the charges.
<h3>Coulombs' law equation</h3>
The equation of Coulomb's law is given as;
F = Kq₁q₂/r²
where;
- K is Coulomb's constant, Nm²/C²
- q₁ is the first charge, C
- q₂ is the second charge, C)
- r is the distance between the charges, m
Thus, the Coulomb's law equation is F = Kq₁q₂/r².
Learn more about Coulomb's law equation here: brainly.com/question/24743340
1j=1newton*meter
force=mass*accel
200N=55x
200/55=3.636......
3.636...-2=1.636.....
1.636 is the deceleration resulting from friction hence the force of friction is 1.636*55=90newtons
90newtons*distance of 10 meters= 900 j of work done by friction