Answer:
7.41 x 10^-10 J
Explanation:
m = 4.5 kg
M = 6.3 kg
d = 1.7 m
The formula for the gravitational potential energy is given by
Where, G is the Universal gravitational constant
G = 6.67 x 10^-11 Nm^2/kg^2
U = - 1.112 x 10^-9 J
Now the separation is tripled, d' = 3 x d = 3 x 1.7 m = 5.1 m
Let the potential energy is U'
The formula for the gravitational potential energy is given by
Where, G is the Universal gravitational constant
G = 6.67 x 10^-11 Nm^2/kg^2
U' = - 3.71 x 10^-10 J
the work done is equal to the change in potential energy
W = U' - U
W = - 3.71 x 10^-10 + 1.112 x 10^-9
W = 7.41 x 10^-10 J
<h2>Answer:</h2>
<u>The number of neutrons is </u><u>47</u>
<h2>Explanation:</h2>
In order to find the number of neutrons we subtract the atomic number from the atomic mass.
In the given case the atomic number is 23 and mass number is 70 so
No of neutrons is 70 -23 = 47
Answer:
read a pleasant story to him Because if you threaten him meaning abusing him then you could go to jail for that if you read him a pleasant story to him then he will go to bed faster if you play an activity game he'll stay up longer and if you watch an exciting TV show he'll stay up longer too soon you just want him to go to bed sleep peacefully and that's why you read him a pleasant story So yeah my answer is read a pleasant story to him so he can go to bed and not be threatened or play an activity game or watch an exciting TV show if you want them to go to sleep That is why I put read a pleasant story to him
We can look at all the ages of the earth since it’s a big crack is reveals many layers of the earth and we can know about chemicals and metals that were in earth and diffrent times
Answer:
(a) 1.21 m/s
(b) 2303.33 J, 152.27 J
Explanation:
m1 = 95 kg, u1 = - 3.750 m/s, m2 = 113 kg, u2 = 5.38 m/s
(a) Let their velocity after striking is v.
By use of conservation of momentum
Momentum before collision = momentum after collision
m1 x u1 + m2 x u2 = (m1 + m2) x v
- 95 x 3.75 + 113 x 5.38 = (95 + 113) x v
v = ( - 356.25 + 607.94) / 208 = 1.21 m /s
(b) Kinetic energy before collision = 1/2 m1 x u1^2 + 1/2 m2 x u2^2
= 0.5 ( 95 x 3.750 x 3.750 + 113 x 5.38 x 5.38)
= 0.5 (1335.94 + 3270.7) = 2303.33 J
Kinetic energy after collision = 1/2 (m1 + m2) v^2
= 0.5 (95 + 113) x 1.21 x 1.21 = 152.27 J
