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1. Find the kinetic energy of a .023 kg bullet moving at 420 m/s.

love history [14]

Answer:

Correct answer: Ek = 2,028.6 J

Explanation:

Ek = m v²/2 = 0.023 · 220² = 0.023 · 176,400/2 = 2,028.6 J

God is with you!!!

8 0

2 years ago

A 65kg person throw a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the s

Kobotan [32]

Well, st first we should find initial momentum for the first person represented in the task which definitely must be :
 $(65+0.045)*2.5$
And then we find the final one : $65*x + 0.045*30$
Then equate them together : $x=2.48 m/s$
So we can get the velocity, which is $is 2.48 m/s$
In that way, according to the main rules of conservation of momentum you can easily find the solution for the second person.
Regards!

6 0

3 years ago

Which of the following is a characteristic of digital data?

Westkost [7]

Answer:

duplication being slightly more expensive.

Explanation:

3 0

2 years ago

how fast will and in what direction will a 20kg object accelerate if one force pushes at a 30 degree angle and another pushes at

DiKsa [7]

Answer:

$|a|=2.83\ m/s^2$

$\theta=75^o$

Explanation:

Net Force And Acceleration

The Newton's second law relates the net force applied on an object of mass m and the acceleration it aquires by

$\vec F_n=m\vec a$

The net force is the vector sum of all forces. In this problem, we are not given the magnitude of each force, only their angles. For the sake of solving the problem and giving a good guide on how to proceed with similar problems, we'll assume both forces have equal magnitudes of F=40 N

The components of the first force are

$\vec F_1=$

$\vec F_1=\ N$

The components of the second force are

$\vec F_2=$

$\vec F_2=\ N$

The net force is

$\vec F_n=$

$\vec F_n=\ N$

The magnitude of the net force is

$|F_n|=\sqrt{14.64^2+54.64^2}$

$|F_n|=\sqrt{3200}=56.57\ N$

The acceleration has a magnitude of

$\displaystyle |a|=\frac{|F_n|}{m}$

$\displaystyle |a|=\frac{56.57}{20}$

$|a|=2.83\ m/s^2$

The direction of the acceleration is the same as the net force:

$\displaystyle tan\theta=\frac{54.64}{14.64}$

$\theta=75^o$

5 0

2 years ago

Calculate the change in length of a Pyrex glass dish (Coefficient of linear expansion for Pyrex is 3 x 10^-6 /C) that is 0.3 met

Readme [11.4K]

Answer:

0.000225 m

Explanation:

Coefficient of linear expansion = $\alpha_L=3\times 10^{-6} /C$

Length = 0.3 meters

ΔT = Change in temperature = 250 °C

Linear expansion

$\frac{\Delta L}{L} = \alpha_L\Delta T\\\Rightarrow \Delta L=\alpha_L\Delta T\times L\\\Rightarrow \Delta L=3\times 10^{-6}\times 0.3\times 250=0.000225\ m$

Change in length of the Pyrex glass dish is 0.000225 m.

3 0

2 years ago