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amid [387]
2 years ago
7

You apply a horizontal force of 25N to push a shopping cart across the parking lot at a constant velocity. a) what is the net fo

rce on the shopping cart ? b) What is the force of friction on the shopping cart ? c) What will happen to the shopping cart if you come across a wet portion of the parking lot and you continue to apply the same force ?
Physics
1 answer:
AlekseyPX2 years ago
4 0

(a) The net force on the shopping cart is zero.

(b) The the force of friction on the shopping cart is 25 N.

(c) When same force is applied to the shopping cart on a wet surface, it will move faster.

<h3>Net force on the shopping cart</h3>

The net force on the shopping cart is calculated as follows;

F(net) = F - Ff

where;

  • F is the applied force
  • Ff is the frictional force

ma = F - Ff

where;

  • a is acceleration of the cart
  • m is mass of the cart

at a constant velocity, a = 0

0 = F - Ff

F(net)  = 0

F = Ff = 25 N

Net force is zero, and frictional force is equal to applied force.

<h3>On wet surface</h3>

Coefficient of kinetic friction of solid surface is greater than that of wet surface.

Since frictional force limit motion, when the frictional force is smaller, the object tends to move faster.

Thus, the cart will move faster on a wet surface due to decrease in friction.

Learn more about frictional force here: brainly.com/question/24386803

#SPJ1

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Steep mountain, due to gravity.
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3 years ago
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M=3000km v=25m/s what’s the momentum
valina [46]
<h3>Answer:</h3>

Momentum of the given body will be : 75000 Kg m/s

<h3>Explanation:</h3>

According to Newton's first law of motion, all bodies continue to be in the state of rest or motion unless an external force is applied on the body. We can use this in the case of momentum also

The formula of momentum is given by :

:\implies \sf\quad \sf \:  P = mv

Here, we are given the mass of the body ( m ) as 3000kg and the velocity of the body ( v ) as 25 m/s. On putting the values in the formula:

\begin{aligned}&:\implies \sf\quad \sf \:  P = mv \\& :\implies \sf\quad \sf \:  P = 3000 \times 25 \\ & :\implies \sf\quad \sf \:   \boxed{ \sf \: P = 75000kgm {s}^{ - 1} } \end{aligned}

Momentum is associated with the mass of the moving body and can be defined as the quantity of motion measured as a product of mass and velocity.

8 0
2 years ago
5. In 1947 Bob Feller, a pitcher for the Cleveland Indians, threw a baseball across the
Darina [25.2K]

The maximum height reached by the ball is 99.2 m

Explanation:

When the ball is thrown straight up, it follows a free fall motion, which is a uniformly accelerated motion with constant acceleration (g=9.8 m/s^2 towards the ground). Therefore, we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

In this problem, we have:

u = 44.1 m/s is the initial vertical velocity of the ball

v = 0 is the final velocity when the ball reaches the maximum height

s is the maximum height

a=-g=-9.8 m/s^2 is the acceleration of gravity (downward, so negative)

Solving for s, we find the maximum height reached by the ball:

s=-\frac{u^2}{2a}=-\frac{44.1^2}{2(-9.8)}=99.2 m

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

3 0
3 years ago
A student standing on a knoll throws a snowball horizontally 4.5 meters above the level ground toward a smokestack 15 meters awa
Elan Coil [88]

Answer:

2.4 m

Explanation:

Consider the motion along the vertical direction

y_{o} = initial position of ball above the ground = 4.5 m

t = time taken by the ball to hit the smokestack = 0.65 s

v_{oy} = initial velocity of the ball along vertical direction

a_{y} = acceleration due to gravity = - 9.8 m/s²

y = position of ball at the time of hitting the smokestack

Using the kinematics equation

y = y_{o} + v_{oy} t + (0.5) a_{y} t^{2}

inserting the above values

y = 4.5 + (0) (0.65) + (0.5) (- 9.8) (0.65)^{2} \\y = 2.4 m

6 0
3 years ago
How long would it take to travel 10 light years at the speed of light?
Vladimir79 [104]

A light year is the DISTANCE light travels through vacuum in 1 year.

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Traveling 1 light year takes 1 year.

Traveling 2 light years takes 2 years.

Traveling 3 light years takes 3 years.

Traveling 10 light years takes 10 years.

If the light is traveling through some other substance, or if the clock is traveling along with the light, then these numbers all change.

YOU cannot travel at the speed of light. We have to just leave it at that

6 0
3 years ago
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