Answer:
the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Explanation:
Given the data in the question;
first we determine the rotational latency
Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms
To get the longest time, lets assume the sector will be found at the last track.
hence we will access all the track, meaning that 127 transitions will be done;
so the track changing time = 127 × 15 = 1905 ms
also, we will look for the sectors, for every track rotations that will be done;
128 × 8.33 = 1066.24 ms
∴The Total Time = 1066.24 ms + 1905 ms
Total Time = 2971.24 ms
Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
The answer is genetic engineering
Answer:
im 99% sure its initial disturbance
Explanation:
B. Greatly affects every part of Texas.
Answer: h = 20.92 m
Explanation: By using the law of conservation of energy, the kinetic energy of the ball equals it potential energy.
Kinetic energy =mv^2/2
Potential energy = mgh
Where m = mass of the object, v = velocity of object = 23.5 m/s
g = acceleration due gravity = 9.8 m/s^2
mv^2/2 = mgh
m cancels out each other on both sides , hence we have that
v^2 = 2gh.
We want the ball to move towards the wall (horizontal motion), hence we need the horizontal component of the velocity since the velocity is inclined at an angle of 30.5 to the ground (horizontal).
Hence v = 23.5 × cos 30.5, v = 20.248 m/s
Recall that v^2 = 2gh
(20.248)^2 = 2×9.8×h
409.98 = 19.6 h
h = 409.98/ 19.6
h = 20.92 m
