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Allushta [10]
3 years ago
9

A. Draw the wave that results when the two waves shown interact through destructive interference. (Image attached)

Physics
2 answers:
katen-ka-za [31]3 years ago
8 0

a) Since these waves are opposite, they will cancel one another (see fig.)

b) If we consider sound speakers, the waves may interfere and destruct each other (like on the attached figure), somewhere they will increase each other (constructive interference).

c) Echo. Go to mountains and scream (beware of avalanche), you'll wonder how many sound waves will come to you from different surfaces against you. This is used in echolocation.

Anna35 [415]3 years ago
7 0

PART A)

Since two waves are in opposite phase

So due to superposition of these type of opposite phase waves the resultant wave is of zero amplitude

This is known as destructive interference

PART B)

Sound from stage seem to be louder at certain seats because of constructive interference of sounds which are coming directly and coming after reflection from walls and other points

This superposition is the result where we get larger amplitude sue to superposition of same phase

PART C)

When a travelling wave bounce back in opposite direction by the change in medium boundary then this phenomenon is known as reflection of wave

If the reflected sound is in opposite phase then the superposition of such sound will give destructive interference

If reflected sound is in same phase then the resultant sounds is always constructive interference

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Answer:

1.

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2.Rotation of Jupiter

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6 0
3 years ago
A plane has a mass of 360,000 kg takes-off at a speed of 300 km/hr. i) What should be the minimum acceleration to take off if th
melomori [17]

Answer:

i) the minimum acceleration to take off is 22500 km/h²

ii) the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) required force that the engine must exert to attain acceleration is 625 kN

Explanation:

Given the data in the question;

mass of plane m = 360,000 kg

take of speed v = 300 km/hr = 83.33 m/s

i)

What should be the minimum acceleration to take off if the length of the runway is 2.00 km

from Newton's equation of motion;

v² = u² + 2as

we know that a plane starts from rest, so; u = 0

given that distance S = 2 km

we substitute

(300)² = 0² + ( 2 × a × 2 )

90000 = 4 × a

a = 90000 / 4

a = 22500 km/h²

Therefore,  the minimum acceleration to take off is 22500 km/h²

ii) At this acceleration, how much time would the plane need from starting to takeoff.

from Newton's equation of motion;

v = u + at

we substitute

300 = 0 + 22500 × t

t = 300 / 22500

t = 0.0133 hrs

Therefore, the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) What force must the engines exert to attain this acceleration

we know that;

F = ma

acceleration a = 22500 km/hr² = 1.736 m/s²

so we substitute

F = 360,000 kg × 1.736 m/s²

F =  624960 N

F = 625 kN

Therefore, required force that the engine must exert to attain acceleration is 625 kN

5 0
3 years ago
A geneticist looks through a microscope to determine the phenotype of a fruit fly. The microscope is set to an overall magnifica
guajiro [1.7K]

Answer:

f_{e} = 1.7 cm

Explanation:

The magnification of the compound microscope is given by the product of the magnification of each lens

        M = M₀ m_{e}

        M = - L/f₀  25/f_{e}

Where f₀ and f_{e} are the focal lengths of the lens and eyepiece, respectively, all values ​​in centimeters

In this exercise they give us the magnification (M = 400X), the focal length of the lens (f₀ = 0.6 cm), the distance of the tube (L = 16 cm), let's look for the focal length of the eyepiece (f_{e})

         f_{e} = - L / f₀ 25 / M

Let's calculate

        f_{e} = - 16 / 0.6 25 / (-400)

        f_{e} = 1.67 cm

The minus sign in the magnification is because the image is inverted.

          f_{e} = 1.7 cm

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