A. Draw the wave that results when the two waves shown interact through destructive interference. (Image attached)
2 answers:
a) Since these waves are opposite, they will cancel one another (see fig.)
b) If we consider sound speakers, the waves may interfere and destruct each other (like on the attached figure), somewhere they will increase each other (constructive interference).
c) Echo. Go to mountains and scream (beware of avalanche), you'll wonder how many sound waves will come to you from different surfaces against you. This is used in echolocation.
PART A)
Since two waves are in opposite phase
So due to superposition of these type of opposite phase waves the resultant wave is of zero amplitude
This is known as destructive interference
PART B)
Sound from stage seem to be louder at certain seats because of constructive interference of sounds which are coming directly and coming after reflection from walls and other points
This superposition is the result where we get larger amplitude sue to superposition of same phase
PART C)
When a travelling wave bounce back in opposite direction by the change in medium boundary then this phenomenon is known as reflection of wave
If the reflected sound is in opposite phase then the superposition of such sound will give destructive interference
If reflected sound is in same phase then the resultant sounds is always constructive interference
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Explanation:
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Explanation:
1) N₂ + O₂ → 2 NO
Kc = [NO]² / ([N₂] [O₂])
Set up an ICE table:
Plug into the equilibrium equation and solve for x.
1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))
1.00×10⁻⁵ = (2x)² / (0.114 − x)²
√(1.00×10⁻⁵) = 2x / (0.114 − x)
0.00316 = 2x / (0.114 − x)
0.00361 − 0.00316x = 2x
0.00361 = 2.00316x
x = 0.00018
The volume is 1.00 L, so the concentrations at equilibrium are:
[N₂] = 0.114 − x = 0.11382
[O₂] = 0.114 − x = 0.11382
[NO] = 2x = 0.00036
2(a) Cl₂ → 2 Cl
Kc = [Cl]² / [Cl₂]
1.2×10⁻⁷ = (2x)² / (2 − x)
1.2×10⁻⁷ (2 − x) = 4x²
2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²
2.4×10⁻⁷ ≈ 4x²
x² ≈ 6×10⁻⁸
x ≈ 0.000245
2x ≈ 0.00049
2(b) F₂ → 2 F
Kc = [F]² / [F₂]
1.2×10⁻⁴ = (2x)² / (2 − x)
1.2×10⁻⁴ (2 − x) = 4x²
2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²
2.4×10⁻⁴ ≈ 4x²
x² ≈ 6×10⁻⁵
x ≈ 0.00775
2x ≈ 0.0155
F₂ dissociates more, so Cl₂ is more stable at 1000 K.