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frosja888 [35]
4 years ago
15

Two steel guitar strings have the same length. String A has a diameter of 0.513 mm and is under 403 N of tension. String B has a

diameter of 1.29 mm and is under a tension of 800 N. Calculate the ratio of the wave speeds, vA/vB, in these two strings.
Physics
1 answer:
Mnenie [13.5K]4 years ago
5 0

Answer:

\frac{v_{A}}{v_{B}} = 1.785

Explanation:

T_{A} = Tension force in string A = 403 N

T_{B} = Tension force in string B = 800 N

d_{A} = diameter of string A = 0.513 mm

d_{B} = diameter of string B = 1.29 mm

v_{A} = wave speed of string A

v_{B} = wave speed of string B

Ratio of the wave speeds is given as

\frac{v_{A}}{v_{B}} = \sqrt{\frac{T_{A}}{T_{B}}} \left ( \frac{d_{B}}{d_{A}} \right )

\frac{v_{A}}{v_{B}} = \sqrt{\frac{403}{800}} \left ( \frac{1.29}{0.513} \right )

\frac{v_{A}}{v_{B}} = 1.785

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Answer:

   s_400 = 16.5 m , s_700 = 29.4 m

Explanation:

The limit of the human eye's solution is determined by the diffraction limit that is given by the expression

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In our case, the dilated pupil has a diameter of approximately 8 mm = 8 10-3 m and the eye responds to a wavelength between 400 nm and 700 nm.

by introducing these values ​​into the formula

                 

λ = 400 nm      θ = 1.22 400 10⁻⁹ / 8 10⁻³ = 6 10⁻⁵ rad

λ = 700 nm     θ = 1.22 700 10⁻⁹ / 8 10⁻³-3 = 1.07 10⁻⁴ rad

Now we can use the definition radians

          θ= s / R

where s is the supported arc and R is the radius. Let's find the sarcos for each case

λ = 400 nm       s_400 = θ R

                         S_400 = 6 10⁻⁵ 275 10³

                         s_400 = 16.5 m

λ = 700 nm s_ 700 = 1.07 10⁻⁴ 275 10³

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8 0
4 years ago
You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the rea
KonstantinChe [14]

Answer : The half-life of this substance will be, 45 minutes.

Explanation :

First we have to calculate the value of rate constant.

Expression for rate law for first order kinetics is given by:

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where,

k = rate constant  = ?

t = time passed by the sample  = 90.3 min

a = initial amount of the reactant = 400

a - x = amount left after decay process = 100

Now put all the given values in above equation, we get

k=\frac{2.303}{90.3min}\log\frac{400}{100}

k=1.54\times 10^{-2}\text{ min}^{-1}

Now we have to calculate the half-life of substance, we use the formula :

k=\frac{0.693}{t_{1/2}}

1.54\times 10^{-2}\text{ min}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=45min

Therefore, the half-life of this substance will be, 45 minutes.

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3 years ago
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Slav-nsk [51]

0.119cm/s is the radius of the balloon increasing when the diameter is 20 cm.

<h3>How big is a circle's radius?</h3>

The radius of a circle is the distance a circle's center from any point along its circumference. Usually, "R" or "r" is used to indicate it.

A circle's diameter cuts through the center and extends from edge to edge, in contrast to a circle's radius, which extends from center to edge. Essentially, a circle is divided in half by its diameter.

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dr/dt = 0.119cm/s.

To know more about radius visit:

brainly.com/question/15053236

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