Answer:
Explanation:
Given that
Radius of disk is
r=23cm=0.23m
The disk starts from rest at t=0
Given angular acceleration
α=3rad/s²
Density of disk is p=8600kg/m³
Energy stored K.E=800J
time taken t=8s
Thickness?
Check attachment for solution
34.916 is the answer to 67.786-32.87 . I found this answer by using a calculator.
Answer:
The magnitude of the acceleration of each block is, a = 2.56 m/s²
The tension in the string is, T = 43.05 N
Explanation:
Given data,
The larger block of mass, M = 8.00 kg
The smaller block of mass, m = 3.50 kg
The formula for Atwood machine is,
Ma = Mg - T
ma = T - mg
Adding those equations,
a (M + m) = g ( M - m)
a = (M + m) / ( M - m)
Substituting the values,
a = (8 + 3.5) / (8 - 3.5)
= 2.56 m/s²
The magnitude of the acceleration of each block is, a = 2.56 m/s²
The tension in the string,
T = m(a + g)
= 3.5 ( 2.56 + 9.8)
= 43.05 N
The tension in the string is, T = 43.05 N
Answer:
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Answer:
at x=0
=W*L/L
and
=W-
Explanation:
Solve for the tension in the left rope, TL, in the special case that x=0. Be sure the result checks with your intuition. Express your answer in terms of W and the dimensions L and x. Not all of these variables may show up in the solution.
moments is the product of force and the perpendicular distance in line of the action of the given force
from the principle of moments which states that the sum of clockwise moments ,must be equal to the sum of anticlockwise moments.
also, sum of upward forces must be equal to sum of downward forces
Going by the aforementioned,
taking moments about 
W*(l-x)=
*(L)
=W*(L-x)/(L)..............1
at x=0
=W*L/L
also
+
=W
=W-