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Deffense [45]
3 years ago
8

The Chevy Corvette Z06 is claimed to accelerate from a standing start to 60 miles per hour in 3 seconds. Estimate its accelerati

on in m/s2 during these 3 seconds (closest answer).
Physics
1 answer:
Vika [28.1K]3 years ago
4 0

Answer:

The acceleration of Chevy Corvette is 8.94\ m/s^2.

Explanation:

Given that,

Initial speed of Chevy Corvette Z06, u = 0 (it starts from rest)

Final speed of Chevy Corvette Z06, v = 60 mph

1 mph = 0.44704 m/s

60 mph = 26.82 m/s

Time, t = 3 seconds

We need to find the acceleration of Chevy Corvette. The rate of change of velocity is called acceleration of an object. It is given by :

a=\dfrac{v-u}{t}

a=\dfrac{v}{t}    

a=\dfrac{26.82\ m/s}{3\ s}      

a=8.94\ m/s^2

So, the acceleration of Chevy Corvette is 8.94\ m/s^2. Hence, this is the required solution.

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You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is
Arlecino [84]

Answer:

a) v=0.5405\ m.s^{-1}

b) v_p'=0.1143\ m.s^{-1}

Explanation:

Given:

mass of ball, m_b=4\ kg

initial speed of the ball, v_b=10\ m.s^{-1}

mass of the person, m_p=70\ kg

a)

Using the conservation of linear momentum:

When the person catches the ball, assuming that the person catches it with an impact without absorbing the shock.

m_b.v_b=(m_b+m_p)v

4\times 10=(4+70)\times  v

v=0.5405\ m.s^{-1}

b)

When the ball hits the person and bounces off with the velocity of v_b'=8\ m.s^{-1}.

Using the conservation of linear momentum:

m_b.v_b+m_p.v_p=m_b.v_b'+m_p.v_p'

where:

v_b'= final speed of the ball after collision

v_p'= final speed of the person after collision

v_p= initial velocity of the person = 0

putting the respective values in the above eq.

4\times 10+0=4\times 8+70\times v_p'

v_p'=0.1143\ m.s^{-1}

8 0
3 years ago
Read 2 more answers
The trajectory of a projectile always ________________. The trajectory of a projectile always ________________. is a straight li
jenyasd209 [6]

Answer:

curves downward, below the initial velocity vector.

Explanation:

Projectile launches are generally divided into two types: the oblique throw and the free fall. The free fall of bodies consists of throwing or abandoning projectiles from a hill or any unevenness that has a height in relation to a frame (usually the ground), while the oblique launch consists of launching a projectile at an angle. any relative to a frame (usually the ground).

Regardless of the type, when reading the paragraph above, we can say that the trajectory of a projectile will always be curved down and below the initial velocity vector.

6 0
3 years ago
Read 2 more answers
Canadian geese migrate essentially along a north-south direction for well over a thousand kilometers in some cases, traveling at
Wewaii [24]

Answer:

θ=19.877⁰

Explanation:

Given data

Velocity Va=34.0 km/h

Velocity Va=100 km/h

To find

Angle θ

Solution  

We want the bird to fly with velocity Vb=100 km/h with an angle θ relative to the ground so that the bird fly due south relative to the ground.From figure which is attached we got

Sinθ=(Va/Vb)

Sinθ=(34.0/100)

θ=Sin⁻¹(34.0/100)

θ=19.877⁰

5 0
3 years ago
Any Answer Would Be Appreciated
-Dominant- [34]

Answer:

last one.Condution and convection are equzlly efficentmethods of heat transfer.

Explanation:

3 0
2 years ago
Give 5 examples of physical properties that could be used to describe a solid
ycow [4]
1.) appearance
2.)texture
3.)color
4.)melting point
5.)odor
8 0
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