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Deffense [45]
4 years ago
8

The Chevy Corvette Z06 is claimed to accelerate from a standing start to 60 miles per hour in 3 seconds. Estimate its accelerati

on in m/s2 during these 3 seconds (closest answer).
Physics
1 answer:
Vika [28.1K]4 years ago
4 0

Answer:

The acceleration of Chevy Corvette is 8.94\ m/s^2.

Explanation:

Given that,

Initial speed of Chevy Corvette Z06, u = 0 (it starts from rest)

Final speed of Chevy Corvette Z06, v = 60 mph

1 mph = 0.44704 m/s

60 mph = 26.82 m/s

Time, t = 3 seconds

We need to find the acceleration of Chevy Corvette. The rate of change of velocity is called acceleration of an object. It is given by :

a=\dfrac{v-u}{t}

a=\dfrac{v}{t}    

a=\dfrac{26.82\ m/s}{3\ s}      

a=8.94\ m/s^2

So, the acceleration of Chevy Corvette is 8.94\ m/s^2. Hence, this is the required solution.

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You are designing a rotating metal flywheel that will be used to store energy. The flywheel is to be a uniform disk with a radiu
Reptile [31]

Answer:

Explanation:

Given that

Radius of disk is

r=23cm=0.23m

The disk starts from rest at t=0

Given angular acceleration

α=3rad/s²

Density of disk is p=8600kg/m³

Energy stored K.E=800J

time taken t=8s

Thickness?

Check attachment for solution

3 0
3 years ago
In physics what does 67.786 – 32.87 equal ?
Zina [86]
34.916 is the answer to 67.786-32.87 . I found this answer by using a calculator.
3 0
3 years ago
Read 2 more answers
1-) Two blocks of mass 3.SO kg and 8.00 kg are connected by a massless string that passes over a
Troyanec [42]

Answer:

The magnitude of the acceleration of each block is, a = 2.56 m/s²

The tension in the string is, T = 43.05 N

Explanation:

Given data,

The larger block of mass, M = 8.00 kg

The smaller block of mass, m = 3.50 kg

The formula for Atwood machine is,

                     Ma = Mg - T

                      ma = T - mg

Adding those equations,

                    a (M + m) = g ( M - m)

                        a = (M + m) / ( M - m)

Substituting the values,

                        a = (8 + 3.5) / (8 - 3.5)

                           = 2.56 m/s²

The magnitude of the acceleration of each block is, a = 2.56 m/s²

The tension in the string,

                       T = m(a + g)

                           = 3.5 ( 2.56 + 9.8)

                            = 43.05 N

The tension in the string is, T = 43.05 N

3 0
3 years ago
Why can concave mirror is used in cosmetic mirror​
tatuchka [14]

Answer:

"When face is placed between the concave mirror and its focus, it produces a magnified image. This enlarged image of face is helpful in makeup as even pores of skin are clearly visible."

4 0
3 years ago
Solve for the tension in the left rope, TL, in the special case that x=0. Be sure the result checks with your intuition. Express
Tatiana [17]

Answer:

at x=0

T_{l}=W*L/L

and

T_{l}=W-T_{r}

Explanation:

Solve for the tension in the left rope, TL, in the special case that x=0. Be sure the result checks with your intuition. Express your answer in terms of W and the dimensions L and x. Not all of these variables may show up in the solution.

moments is the product of force and the perpendicular distance in line of the action of the given force

from the principle of moments which states that the sum of clockwise moments ,must be equal to the sum of anticlockwise moments.

also, sum of upward forces must be equal to sum of downward forces

Going by the aforementioned,

taking moments about T_{r}

W*(l-x)=T_{l}*(L)

T_{l}=W*(L-x)/(L)..............1

at x=0

T_{l}=W*L/L

also

T_{l}+ T_{r}=W

T_{l}=W-T_{r}

3 0
4 years ago
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