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harkovskaia [24]
2 years ago
8

A reaction produces 0.801 moles of H2O. How many molecules of H20 are produced?

Chemistry
1 answer:
timama [110]2 years ago
6 0

Answer:

1 mole of molecules = 6.022 × 10²³ molecules

1 = 6.022 × 10²³ molecules / mole

Multiplying a number with [6.022 × 10²³ molecules / mole] is like multiplying the number with 1 so  0.877 mole × 6.022 × 10²³ molecules / mole = 5.28 × 10²³ molecules

5.28 × 10²³ molecules of water is produced.

Explanation:

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If you place 1.0 L of ethanol (C2H5OH) in a small laboratory that is 3.0 m long, 2.0 m wide, and 2.0 m high, will all the alcohol evaporate? If some liquid remains, how much will there be? The vapor pressure of ethyl alcohol at 25 °C is 59 mm Hg, and the density of the liquid at this temperature is 0.785g/cm^3 .

will all the alcohol evaporate? or none at all?

Answer:

Yes, all the ethanol present in the laboratory will evaporate since the mole of ethanol present in vapor is greater. The volume of ethanol left will therefore  be zero.

Explanation:

Given that:

The volume of alcohol which is placed in a small laboratory = 1.0 L

Vapor pressure of ethyl alcohol  at 25 ° C = 59 mmHg

Converting 59 mmHg to atm ; since 1 atm = 760 mmHg;

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= \frac{59}{760}atm

= 0.078 atm

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= ( 25 + 273 K)

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Converting the volume of laboratory to liter;

since 1 m³ = 100 L; Then, we  have:

15 × 1000 = 15,000 L

Using ideal gas equation to determine the moles of ethanol in vapor phase; we have:

PV = nRT

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n = \frac{PV}{RT}

n = \frac{0.078 * 15000}{0.082*290}

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Moles of ethanol in 1.0 L bottle can be calculated as follows:

Since  numbers of moles = \frac{mass}{molar mass}

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number of moles = \frac{density*volume }{molar mass of ethanol}

number of moles =\frac{0.785g/cm^3*1000cm^3}{46.07g/mol}

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Thus , all the ethanol present in the laboratory will evaporate since the mole of ethanol present in vapor is greater. The volume of ethanol left will therefore be zero.

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3 years ago
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Answer:

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Explanation:

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