Answer: The average atomic mass of oxygen is 15.999 amu
Explanation:
Mass of isotope O-16 = 15.995 amu
% abundance of isotope O-16= 99.759 % = 
Mass of isotope O-17 = 16.995 amu
% abundance of isotope O-17 = 0.037% = 
Mass of isotope O-18 = 17.999 amu
% abundance of isotope O-18 = 0.204% = 
Formula used for average atomic mass of an element :

![A=\sum[(15.995\times 0.99759)+(16.995\times 0.00037)+(17.999 \times 0.00204)]](https://tex.z-dn.net/?f=A%3D%5Csum%5B%2815.995%5Ctimes%200.99759%29%2B%2816.995%5Ctimes%200.00037%29%2B%2817.999%20%5Ctimes%200.00204%29%5D)

Thus the average atomic mass of oxygen is 15.999 amu
Answer:

Explanation:
<em>Telophase is the process that separates the duplicated genetic material carried in the nucleus of a parent cell into two identical daughter cells.</em>
<em />
<em />
<em />
Answer: The original volume in liters was 0.0707L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,

where,
= initial pressure of gas = 0.85 atm
= final pressure of gas = 456 mm Hg = 0.60 atm (760mmHg=1atm)
= initial volume of gas = ?
= final volume of gas = 94.0 ml
= initial temperature of gas = 
= final temperature of gas =

Now put all the given values in the above equation, we get:

(1L=1000ml)
Thus the original volume in liters was 0.0707L
I think the correct answer is c if not it’s d