Answer:
2Cu2^+ + 2I^- ----> 2Cu^+ + I2
Explanation:
The reaction performed in the experiment is;
2 Cu(NO3)2 + 4 KI → 2 CuI (s) + 4 KNO3 + I2
The iodide ions reduces Cu^2+ to Cu^+ which is insoluble in water hence the precipitate. This is so because iodine is a good oxidizing agent seeing that it requires one electron to fill its outermost shell. Potassium on the other hand is a good reducing agent since it easily looses its one electron.
The oxidation - reduction equation is as follows;
2Cu2^+ + 2e ----> 2Cu^+ reduction half equation
2I^- ----> I2 + 2e. Oxidation half equation
Balanced redox reaction equation;
2Cu2^+ + 2I^- ----> 2Cu^+ + I2
Geometry name is trigonal bypyramidal
non-polar
Answer:
B. Na2SO3 is one of the reactants
Explanation:
Answer:
4.94x10^24 atoms Zn
Explanation:
By definition, there are 6.022x10^23 atoms in a mole of a substance. This is a conversion factor:
(6.022x10^23 atoms/mole)
(8.2 moles Zn)* (6.022x10^23 atoms/mole) = 4.94x10^24 atoms Zn