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Maslowich
2 years ago
15

What is 0.05 kg mass in milligrams?

Chemistry
2 answers:
Crank2 years ago
7 0
0.05 kg = 50000 milligrams
liberstina [14]2 years ago
3 0
Convert 0.05 Kilograms to Milligrams (kg to mg) with our conversion calculator and conversion tables. To convert 0.05 kg to mg use direct conversion formula below. 
0.05 kg = 50000 mg.
<span>You also can convert 0.05 Kilograms to other Weight (popular) units.</span>
You might be interested in
a. What is the definition of a mole? b. What is the abbreviation for mole? SARM c. How many particles are in one mole? d. What n
ycow [4]

Mole is base unit of substance. The number of particles in one mole is equal to 6.022 × 10²³. The number of particle in a mole is called as Avogadro's number.

The mole of substance is the amount of substance that contain elementary particles as the number of atoms. the symbol of mole is mol. it is the SI unit of amount of substance. The number particles are ion one mole of substances is 6.022 × 10²³. The number of particles in one mole of substance is called as Avogadro's number.

Thus, Mole is base unit of substance. The number of particles in one mole is equal to 6.022 × 10²³. The number of particle in a mole is called as Avogadro's number.

To learn more about moles here

brainly.com/question/26416088

#SPJ1

7 0
1 year ago
A 0.2688 g sample of a monoprotic acid neutralized 16.4 mL of 0.08133 M KOH solution. Calculate the molar mass of the acid
ivanzaharov [21]

Answer:

202 g/mol

Explanation:

Let's consider the neutralization between a generic monoprotic acid and KOH.

HA + KOH → KA + H₂O

The moles of KOH that reacted are:

0.0164 L × 0.08133 mol/L = 1.33 × 10⁻³ mol

The molar ratio of HA to KOH is 1:1. Then, the moles of HA that reacted are 1.33 × 10⁻³ moles.

1.33 × 10⁻³ moles of HA have a mass of 0.2688 g. The molar mass of the acid is:

0.2688 g/1.33 × 10⁻³ mol = 202 g/mol

3 0
3 years ago
Which tool can be used to measure the volume of a liquid to one decimal place?
pentagon [3]
The tool to measure the liquid is a measuring cylinder.
3 0
3 years ago
Read 2 more answers
A 150.0mL sample of an aqueous solution at 25C contains 15.2mg of an unknown nonelectrolyte compound. If the solution has an osm
Nookie1986 [14]

Answer:

MM = 225.11 g/mol

Explanation:

In this case, let's analyze the data.

We have a 15.2 mg of an unknown electrolyte in 150 mL of solution. The osmotic pressure is 8.44 Torr, and we want the molecular mass of the unknown.

The osmotic pressure can be calculated using the following expression:

π = CRT   (1)    

π: osmotic pressure (8.44 Torr * 1 atm / 760 Torr = 0.011 atm)

C: Concentration of the unknown in the solution

R: universal constant of gases (0.082 L atm / K mol)

T: temperature in Kelvin (25 + 273 = 298 K)

From this expression, we can either solve for C, and then use another expression to calculate the molecular mass, or we can just replace the expressions in the above formula, to get the direct molecular mass. In this case, we'll follow the second method.

Concentration or molarity of a substance can be calculated using:

C = moles / V  (2)

And moles can be calculated using this expression:

moles = m / MM   (3)

Replacing (3) in (2), and then in (1) we have:

C = m / MM * V

π = m * RT / MM * V   (4)

and now, we can solve for MM:

MM = mRT / π V  (5)

Now, we just need to replace the given data into the above expression to get the value of the molecular mass:

MM = (15.2 / 1000) * 0.082 * 298 / 0.011 * 0.150

<h2>MM = 225.11 g/mol</h2>

Hope this helps

3 0
3 years ago
some infrared radiation reaches earth and sum does not with part does reach earth longer wave length or short wave length
Ede4ka [16]
The answer is long wave length because long wave lengths contians less energy, and would not harm living things such as plants and animals. the more engey a wave length has, the less harmful it is.

short wave length: lots of energy, extremely hot. (examples: gamma rays, and UV (ultraviolet) rays.

long wave lengths: not much energy, safe for humans and other life on Earth.

hopefully this helps.

4 0
3 years ago
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