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evablogger [386]
3 years ago
13

A group of students collects data to determine whether compounds were ionic or covalent. They placed each compound in a small bo

wl and stuck two open ends of a battery-powered circuit in the compound. image Based on the student’s data, can they determine which substances are ionic, and which are covalent?
Chemistry
1 answer:
yan [13]3 years ago
8 0

Answer:

the answer is B.  

No, as ionic compounds are only conductive in an aqueous (water) solution

Explanation: i just know

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You have a cup of hot water and you dissolve as much salt in it as possible. You then put the cup into the refrigerator and you
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Some of the salt would settle out. When the water was heated, it was able to absorb more salt than usual. This is known as super saturation. When the water is frozen it cannot hold as much salt, so some of it has to come out.
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What is the molarity of HCl if 34.81 mL of a solution of HCl contain 0.3297 g of HCl?
Temka [501]

Answer:

0.2598 M

Explanation:

Molarity is mol/L, so we have to convert the grams to moles and the mL to L. To convert between grams and moles you need the molar mass of the compound, which is 36.46g/mol.

0.3297gHCl*\frac{1molHCl}{36.46gHCL} = 0.00904279 mol HCl

34.81 mLHCl * \frac{1L}{1000L} = 0.03481 L HCl

\frac{0.00904279molHCl}{0.03481 L HCl} = 0.25977554 mol/L

Round to the lowest number of significant figures = 0.2598 M

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3 years ago
Panuto: Punan ang talaan sa ibaba at suriing mabuti ang sarili upang higit mong
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The answer is 2

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4 0
3 years ago
A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num
-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}

\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}

<em>B) Radius</em>

\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}

V = \frac{ 4}{3 }\pi r^{3}

r^{3} = \frac{3V }{4 \pi }\

r= \sqrt [3]{ \frac{3V }{4 \pi } }

r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}

3 0
3 years ago
Saturated hydrocarbon molecules may be bonded in which type of structure?
poizon [28]
<span>all of the above can be saturated molecules </span>
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