Answer:
100 J
Explanation:
From the question, The work done by the forces in moving the box is given as
W = FxdcosФ+Fydcosα................... Equation 1
Where W = Work done, Fx = force acting parallel to the floor, d = distance moved by the box, Ф = angle the parallel force makes with the floor, Fy = force acting perpendicular to the floor, α = angle the perpendicular force make with the floor.
Give: Fx = 10 N, d = 20 m, Fy = 5 N, Ф = 0°, α = 90°
Substitute into equation 1
W = 10×10×cos0°+5×20×cos90°
W = 10×10×1+0
W = 100 J.
Note: The work done by the perpendicular force is zero
Hence the work done = 100 J
Answer:
a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.
Explanation:
During the motion of the rock while it is in downward motion we can say
since it is performing circular motion so we will have its acceleration towards its center
So at the lowest point of the path we can say
so correct answer is
a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.
Answer:
e) half
Explanation:
as we know relation b/w charge(Q) , capacitance (C) and voltage (V) is
Q = CV ...........(i)
we also know capacitance of a capacitor for separation d and area A is
C = ∈₀A/d ...........(ii)
from the above equation it is clear that C is inversely proportional to separation if separation doubled capacitance will reduced to half and from equation first charge is directly proportional to capacitance.
that s why magnitude of charge will reduced to half
so option (e) is right answer
Answer:
a.) volume = 70cm^3
b.) mass = 805 grams
Explanation:
see the explanation in attachment.
