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lakkis [162]
4 years ago
10

What mass of barium nitrate is dissolved in 21.29 mL of a 3.38 M solution?

Chemistry
1 answer:
Ostrovityanka [42]4 years ago
7 0

Answer:

18.81 g

Explanation:

We are given;

  • Volume of Barium nitrate as 21.29 mL or 0.02129 L
  • Molarity of Barium nitrate as 3.38 M

We are required to determine the mass of Barium nitrate

Step 1: Determine the number of moles of Barium nitrate

Number of moles = Molarity × Volume

                             = 3.38 M × 0.02129 L

                             = 0.07196 moles

Step 2: Determine the mass of Barium nitrate

We know that;

Mass = Number of moles × Molar mass

Molar mass of Barium Nitrate is 261.337 g/mol

Therefore;

Mass of barium nitrate = 0.07196 moles × 261.337 g/mol

                                     = 18.8058 g

                                     = 18.81 g

Thus, the mass of barium nitrate dissolved is 18.81 g

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6 0
2 years ago
Volume of HCl used 25.0mL 4 l
borishaifa [10]

Answer:

1.0 M

Explanation:

Reaction equation;

KOH(aq) + HCl(aq) -----> KCl(aq) + H2O(l)

Concentration of acid CA = ?

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8 0
4 years ago
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