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ddd [48]
4 years ago
13

18°C = -255 К OOK О18 К 291 К

Physics
1 answer:
masha68 [24]4 years ago
7 0

Answer:

I think the answer for this question is 291 K

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Edward runs with a speed of 3m/s. How long would it take him to run 2km? Give your answer in seconds to four significant figures
Whitepunk [10]

Answer:

666.6 seconds

Explanation:

if he runs at 3m/sec he will achieve the goal of 2000m in 666.6 seconds. just divide - 3/2000.

note we have changed 2km to 2000metres

5 0
3 years ago
Characteristics we use to tell the difference between kinds of matter are called___ properties
d1i1m1o1n [39]

Answer:

I believe it's called qualitative

Explanation:

8 0
3 years ago
One of Lex Luthor's henchman attacks Superman, shooting a rapid-fire stream of 3.3 g bullets at him at a rate of 112/min. The sp
igor_vitrenko [27]

Answer:

3.2451N

Explanation:

Mass of the bullet (m) = 3.3g = 3.3*10^{-3}Kg

Speed of the bullet (V)= 527m/s

Rate of bullet (r) = 112/min = 1.866\sec

We can calculate with this information the average acceleration of bullets

a=V*r = 527\frac{m}{s}\frac{1.866}{s} = 983.38m/s^2

The force is given by,

F=ma\\F=(3.3*10^{-3})*983.38m/s^2 = 3.2451N

That is just because he is Superman.

4 0
3 years ago
A stone is dropped from the upper observation deck of a tower, 750 m above the ground. (assume g = 9.8 m/s2.) (a) find the dista
Gekata [30.6K]
(a) The stone moves by uniform accelerated motion, with constant acceleration g=9.81 m/s^2 directed downwards, and its initial vertical position at time t=0 is 750 m. So, the vertical position (in meters) at any time t can be written as
y(t)= y_0 -  \frac{1}{2}gt^2= 750 - 4.9 t^2

(b) The time the stone takes to reach the ground is the time at which the vertical position of the stone becomes zero: y(t)=0. So, we can write
750-4.9 t^2 = 0
from which we find the time t after which the stone reaches the ground:
t= \sqrt{\frac{750 m}{4.9 m/s^2 }}= 12.37 s

(c) The velocity of the stone at time t can be written as
v(t) = -gt
because it is an accelerated motion with initial speed zero. Substituting t=12.37 s, we find the final velocity of the stone:
v(12.37 s)=-(9.81 m/s^2)(12.37 s)=-121.3 m/s

(d) if the stone has an initial velocity of v_0 = 6 m/s, then its law of motion would be
y(t)=y_0 - v_0t -  \frac{1}{2}gt^2
and we can find the time it needs to reach the ground by requiring again y(t)=0:
0=750 - 6t - 4.9 t^2
which has two solutions: one is negative so we neglect it, while the second one is t=11.78 s, so this is the time after which the stone reaches the ground.

5 0
3 years ago
A woman performs 2000 J of work in order to push a cart full of groceries 50 meters. How much force did she apply to the cart? *
ad-work [718]
They will give you 4000
4 0
3 years ago
Read 2 more answers
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