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aleksklad [387]

3 years ago

12

A rectangular wooden block measures 10.0cm x 4.00cm x 2.00cm. when the block is placed in water, it floats horizontally, with it

s bottom face 1.65cm below the surface. what is the density of the wood? show and explain your work.

1 answer:

bekas [8.4K]3 years ago

6 0

Answer:

The density of the wood is

ρ₂ = 1.21 g / cm³

Explanation:

The block measures

V₁ = 10.0 cm * 4.0 cm * 2.0 cm

V₁ = 80 cm³

Now the block measures under the water getting just the face below as 1.65 cm

V₂ = 10.0 cm * 4.0 cm * 1.65 cm

V₂ = 66 cm³

So to determine the density knowing the mass are the same as the weight

ρ₁ * V₁ = ρ₂ * V₂

Using the density of the water as a

ρ₁ = 1 g / cm ³

1 g / cm³ * 80 cm ³ = ρ₂ * 66 cm³

ρ₂ = 1.21 g / cm³

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Part c)

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$t$ - Time, measured in seconds.

$\phi$ - Phase, measured in radians.

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