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aleksklad [387]
3 years ago
12

A rectangular wooden block measures 10.0cm x 4.00cm x 2.00cm. when the block is placed in water, it floats horizontally, with it

s bottom face 1.65cm below the surface. what is the density of the wood? show and explain your work.
Physics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

The density of the wood is

ρ₂ = 1.21 g / cm³

Explanation:

The block measures

V₁ = 10.0 cm * 4.0 cm * 2.0 cm

V₁ = 80 cm³

Now the block measures under the water getting just the face below as 1.65 cm

V₂ = 10.0 cm * 4.0 cm * 1.65 cm

V₂ = 66 cm³

So to determine the density knowing the mass are the same as the weight

ρ₁ * V₁ = ρ₂ * V₂

Using the density of the water as a

ρ₁ = 1 g / cm ³

1 g / cm³ * 80 cm ³ = ρ₂ * 66 cm³

ρ₂ = 1.21 g / cm³

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matrenka [14]

Answer:

Part a)

T = 42 N

Part b)

v_f = 11.8 m/s

Part c)

t = 1.7 s

Part d)

F = 159.7 N

Explanation:

Part a)

While bucket is falling downwards we have force equation of the bucket given as

mg - T = ma

for uniform cylinder we will have

TR = I\alpha

so we have

T = \frac{1}{2}MR^2(\frac{a}{R^2})

T = \frac{1}{2}Ma

now we have

mg = (\frac{M}{2} + m)a

a = \frac{mg}{(\frac{M}{2} + m)}

a = \frac{15 \times 9.81}{(6 + 15)}

a = 7 m/s^2

now we have

T = \frac{12 \times 7}{2}

T = 42 N

Part b)

speed of the bucket can be found using kinematics

so we have

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2(7)(10)

v_f = 11.8 m/s

Part c)

now in order to find the time of fall we can use another equation

v_f - v_i = at

11.8 - 0 = 7 t

t = 1.7 s

Part d)

as we know that cylinder is at rest and not moving downwards

so here we can use force balance

F = T + Mg

F = 42 + (12 \times 9.81)

F = 159.7 N

5 0
3 years ago
What effect does time have on the speed of a moving object
sergejj [24]
Velocity is d/t distance over time. Increase velocity (speed) decrease. Increase d velocity increases.
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1.20 Newton force is working on a 250 gram object. What is the acceleration?
Leokris [45]

Answer:

The answer is B

Explanation:

250g = 0.25kg

F = m × a

a = F/m

= 1.2/0.25

= 4.8m/s²

7 0
2 years ago
Nuclear _________ reactions convert protons into helium; thus, becoming the source of all energy radiated by the sun. A) fission
Bogdan [553]

Nuclear fusion reactions convert protons into helium; thus, becoming the source of all energy radiated by the sun.

Answer: Option D

<u>Explanation:</u>

Nuclear fusion reaction is one among the two nuclear reactions in which the atoms nucleus interact with each other to produce the products. In nuclear fusion, two smaller atoms react together to form a new atom with bigger size.

So large amount of energy is required to start the nuclear fusion reaction. The fusion reactions mostly occurs in stars. The illumination in Stars even the Sun is due to nuclear fusion reaction occurring with the atoms present in them.

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3 0
2 years ago
A 0.40 kg mass hangs on a spring with a spring constant of 12 N/m. The system oscillated with a constant amplitude of 12 cm. Wha
Vaselesa [24]

Answer:

The maximum acceleration of the system is 359.970 centimeters per square second.

Explanation:

The motion of the mass-spring system is represented by the following formula:

x(t) = A\cdot \cos (\omega \cdot t + \phi)

Where:

x(t) - Position of the mass with respect to the equilibrium position, measured in centimeters.

A - Amplitude of the mass-spring system, measured in centimeters.

\omega - Angular frequency, measured in radians per second.

t - Time, measured in seconds.

\phi - Phase, measured in radians.

The acceleration experimented by the mass is obtained by deriving the position equation twice:

a (t) = -\omega^{2}\cdot A \cdot \cos (\omega\cdot t + \phi)

Where the maximum acceleration of the system is represented by \omega^{2}\cdot A.

The natural frequency of the mass-spring system is:

\omega = \sqrt{\frac{k}{m} }

Where:

k - Spring constant, measured in newtons per meter.

m - Mass, measured in kilograms.

If k = 12\,\frac{N}{m} and m = 0.40\,kg, the natural frequency is:

\omega = \sqrt{\frac{12\,\frac{N}{m} }{0.40\,kg} }

\omega \approx 5.477\,\frac{rad}{s}

Lastly, the maximum acceleration of the system is:

a_{max} = \left(5.477\,\frac{rad}{s})^{2}\cdot (12\,cm)

a_{max} = 359.970\,\frac{cm}{s^{2}}

The maximum acceleration of the system is 359.970 centimeters per square second.

7 0
3 years ago
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