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ch4aika [34]
3 years ago
7

A driver looks at her dashboard and reads that she is traveling at 100 kilometers per hour. What does this measurement represent

?
A) time
B) distance
C) average speed
D) instantaneous speed
Physics
2 answers:
Sergio039 [100]3 years ago
8 0
C. Average Speed 
because they are not giving you a specific time or distance so it must relate to speed. her average speed it 100 km/hr therefore the answer should be C
Dmitry_Shevchenko [17]3 years ago
6 0
The answer is C!! 100 kilometers per hour is an average speed.
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If the voltage across a circuit element of constant resistance is doubled, how is the current through the circuit element affect
Karo-lina-s [1.5K]

Answer:

The current through the circuit element will also be doubled.

Explanation:

The relationship between voltage and current of a circuit element is given by Ohm's Law. According to Ohm's Law:

Voltage = (Resistance)(Current)

If the resistance of the element is kept constant, the relation between Voltage and Current through that element becomes as follows:

Voltage = (Constant)(Current)

Voltage α Current

Thus, the voltage is directly proportional to the current for constant value of the resistance.

Therefore, when the voltage across a circuit element of constant resistance is doubled, <u>the current through the circuit element will also be doubled.</u>

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3 years ago
If a compound forms by ionic bonding, which is not true?
MrRa [10]

Answer:is deez nut;D

Explanation:

because u gay...

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3 years ago
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A 19 nC charge is moved in a uniform electric field. The electric field does 5.3 μJ of work as the charge moves from point A to
Marizza181 [45]

Answer:

The potential difference between points A and B is 278.95 volts.

The potential difference between points B and C is -642.10 volts.

The potential difference between points A and C is -363.15 volts.

Explanation:

Given :

Charge of the particle, q = 19 nC = 19 x 10⁻⁹ C

Work is done to move a charge from point A to B, W₁ = 5.3 μJ

Work done to move a charge from point B to C, W₂ = -12.2 μJ

Let V₁ be the potential difference between point A and B, V₂ be the potential difference between point B and C and V₃ be the potential difference between point A and C.

The relation between work done and potential difference is:

W = qV  

V = W/q    ....(1)

Using equation (1), the potential difference between points A and B is:

V_{1}=\frac{W_{1} }{q}

Substitute the suitable values in the above equation.

V_{1} =\frac{5.3\times10^{-6} }{19\times10^{-9} }

V₁ = 278.95 V

Using equation (1), the potential difference between points B and C is:

V_{2}=\frac{W_{2} }{q}

Substitute the suitable values in the above equation.

V_{2} =\frac{-12.2\times10^{-6} }{19\times10^{-9} }

V₂ = -642.10 V

The potential difference between points A and C is:

V₃ = V₁ + V₂

V₃ = 278.95 - 642.10

V₃ = -363.15 V

8 0
3 years ago
A 2 L balloon filled with gas is warmed from 280 K to 700 K. What is the volume of the gas after it is heated?
irakobra [83]

Answer:

New volume, v2 = 0.8L

Explanation:

<u>Given the following data;</u>

Original Volume = 2L

Original Temperature = 280K

New Temperature = 700K

To find new volume V2, we would use Charles' law.

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

VT = K

\frac{V1}{T1} = \frac{V2}{T2}

\frac{V1}{T1} = \frac{V2}{T2}

Making V2 as the subject formula, we have;

V_{2}= \frac{V1}{T1} * T_{2}

V_{2}= \frac{2}{700} * 280

V_{2}= 0.0029 * 280

V2 = 0.8L

Therefore, the volume of the gas after it is heated is 0.8L.

7 0
3 years ago
A car with a mass of 2.0×10^3 kg is traveling at 15m/s .what is the momentum of the car ?
Maurinko [17]
Hello,

<span>A car with a mass of 2.0×10^3 kg is traveling at 15m/s. We need to find the momentum of the car. To do so, follow this formula:

p=mv

Where,

p = momentum 
m = mass
v = </span>velocity

The cars mass is 2.0E3 and its velocity is 15m/s. Therefore:

p=2.0  x 10^3 *15 or 2000(15)

p=30000

Thus, the cars momentum is 30000 kg m/s

Faith xoxo
7 0
3 years ago
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