Answer:
50°C = 122 Fahrenheit
Explanation:
Here, we need to convert 50°C to F i.e. Fahrenheit. The conversion formula from degree Celsius to Fahrenheit is as follows :
Where, 
So, 50 degree Celsius is equal to 122 degree Fahrenheit. Hence, this is the required solution.
Well you never specified what you're asking... however, this might help you learn the concepts of displacements and magnitude.
: The official displacement formula is as follows: s = sf - si. s = displacement; si = initial position; sf = final position
magnitude is the quantitative value of seismic energy. It is a specific value having no relation with distance and direction of the epicentre.
the magnitude of a vector in any dimension. For a 2d vector the formula is [math]|z| = \sqrt{x^2+y^2}[/math], where x and y are the x and y components of the vector respectively.
Both matter and energy can eneter and exit an <span>Open System only. A.</span>
Answer:
Preassure plate
Explanation:
The flywheel, clutch disc, pressure plate, throw-out bearing clutch fork, and the pilot bearing are the components of a clutch. It works when the flywheel bolts onto the crankshaft and therefore the <em>pressure plate bolts back into the flywheel.</em>
I hope you find this information useful and interesting! Good luck!
Answer:
6400 m
Explanation:
You need to use the bulk modulus, K:
K = ρ dP/dρ
where ρ is density and P is pressure
Since ρ is changing by very little, we can say:
K ≈ ρ ΔP/Δρ
Therefore, solving for ΔP:
ΔP = K Δρ / ρ
We can calculate K from Young's modulus (E) and Poisson's ratio (ν):
K = E / (3 (1 - 2ν))
Substituting:
ΔP = E / (3 (1 - 2ν)) (Δρ / ρ)
Before compression:
ρ = m / V
After compression:
ρ+Δρ = m / (V - 0.001 V)
ρ+Δρ = m / (0.999 V)
ρ+Δρ = ρ / 0.999
1 + (Δρ/ρ) = 1 / 0.999
Δρ/ρ = (1 / 0.999) - 1
Δρ/ρ = 0.001 / 0.999
Given:
E = 69 GPa = 69×10⁹ Pa
ν = 0.32
ΔP = 69×10⁹ Pa / (3 (1 - 2×0.32)) (0.001/0.999)
ΔP = 64.0×10⁶ Pa
If we assume seawater density is constant at 1027 kg/m³, then:
ρgh = P
(1027 kg/m³) (9.81 m/s²) h = 64.0×10⁶ Pa
h = 6350 m
Rounded to two sig-figs, the ocean depth at which the sphere's volume is reduced by 0.10% is approximately 6400 m.
