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Mashcka [7]
3 years ago
6

How many grams of CO are needed to produce 209.7 g Fe? Fe2O3+3CO⟶3CO2+2Fe

Chemistry
1 answer:
kirill115 [55]3 years ago
4 0

Answer:

157.8 g

Explanation:

Step 1: Write the balanced equation

Fe₂O₃ + 3 CO ⟶ 3 CO₂ + 2 Fe

Step 2: Calculate the moles corresponding to 209.7 g of Fe

The molar mass of Fe is 55.85 g/mol

209.7 g × 1 mol/55.85 g = 3.755 mol

Step 3: Calculate the moles of CO needed to produce 3.755 moles of Fe

The molar ratio of CO to Fe is 3:2. The moles of CO needed are 3/2 × 3.755 = 5.633 mol

Step 4: Calculate the mass corresponding to 5.633 moles of CO

The molar mass of CO is 28.01 g/mol.

5.633 mol × 28.01 g/mol = 157.8 g

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a ceramic or metal container in which metals or other substances may be melted or subjected to very high temperatures.

"the crucible tipped and the mold filled with liquid metal"

a situation of severe trial, or in which different elements interact, leading to the creation of something new.

"their relationship was forged in the crucible of war"

3 0
3 years ago
Urea, CO(NH2)2, is manufactured on a large scale for use in producing urea-formaldehyde plastics and as a fertilizer. What is th
Pachacha [2.7K]

Answer:

5.004kg

Explanation:

Combustion of carbon

C+O2=CO2

from the relationship of molar ratio

mass of carbon/molar mass of carbon=volume of CO2 produced\molar vol(22.4 dm3)

mass of carbon =1000kg

atomic mass of carbon =12

volume of CO2 produced=1000×22.4/12

volume of CO2 produced =1866.6dm3

from the combustion reaction equation provided

CO2 (g) + 2NH3 (g) ⟶ CO (NH2 )2 (s) + H2 O(l)

applying the same relationship of molar ratio

no of mole of CO2=no of mole of urea

therefore

vol of CO2\22.4=mass of urea/molar mass of urea

molar mass of urea=60.06g/mol

from the first calculation

vol of CO2=1866.6dm3

mass of urea=1866.6×60.06/22.4

mass of urea=5004.82kg

7 0
3 years ago
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What is anything that has mass and volume
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Anything that has mass and volume (takes up space) is called matter.
3 0
3 years ago
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What is the pOH of a solution of HNO3 that has [OH-] = 9.50 10-9 M?
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Answer:

The pOH of HNO₃ solution that ha OH⁻ concentration 9.50 ×10⁻⁹M is 8.

Explanation:

Given data:

[OH⁻] = 9.50 ×10⁻⁹M

pOH = ?

Solution:

pOH = -log[OH⁻]

Now we will put the value of OH⁻ concentration.

pOH = -log[9.50 ×10⁻⁹M]

pOH = 8

Thus the pOH of HNO₃ solution that ha OH⁻ concentration 9.50 ×10⁻⁹M is 8.

6 0
3 years ago
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A 0.200 g sample of unknown metal x is dropped into hydrochloride acid and realeases 80.3 mL of hydrogen gas at STP using ideal
s344n2d4d5 [400]

Answer:

The number of mole of the unknown metal is 3.58×10¯³ mole

Explanation:

We'll begin by calculating the number of mole hydrogen gas, H2 that will occupy 80.3 mL at stp.

This is illustrated below:

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1 mole of any occupy 22.4L or 22400 mL at stp.

1 mole of H2 occupies 22400 mL at stp.

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Therefore, 3.58×10¯³ mole of Hydrogen gas was released.

Now, we can determine the mole of the unknown metal as follow:

The balanced equation for the reaction is given below:

X + 2HCl —> XCl2 + H2

From the balanced equation above,

1 mole of the unknown metal reacted to produce 1 mole of H2.

Therefore, 3.58×10¯³ mole of the unknown metal will also react to produce 3.58×10¯³ mole of H2.

Therefore, the number of mole of the unknown compound is 3.58×10¯³ mole.

5 0
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