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Mashcka [7]
2 years ago
6

How many grams of CO are needed to produce 209.7 g Fe? Fe2O3+3CO⟶3CO2+2Fe

Chemistry
1 answer:
kirill115 [55]2 years ago
4 0

Answer:

157.8 g

Explanation:

Step 1: Write the balanced equation

Fe₂O₃ + 3 CO ⟶ 3 CO₂ + 2 Fe

Step 2: Calculate the moles corresponding to 209.7 g of Fe

The molar mass of Fe is 55.85 g/mol

209.7 g × 1 mol/55.85 g = 3.755 mol

Step 3: Calculate the moles of CO needed to produce 3.755 moles of Fe

The molar ratio of CO to Fe is 3:2. The moles of CO needed are 3/2 × 3.755 = 5.633 mol

Step 4: Calculate the mass corresponding to 5.633 moles of CO

The molar mass of CO is 28.01 g/mol.

5.633 mol × 28.01 g/mol = 157.8 g

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sergiy2304 [10]

Answer:

D. -1882J

Explanation:

We can solve the energy released in a chemical reaction in an aqueous medium using the equation:

Q = -m*C*ΔT

<em>Where Q is energy (In J),</em>

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<em>C is specific heat of water (4.184J/g°C)</em>

<em>And ΔT is change in temperature (25.00°C - 15.00°C = 10.00°C)</em>

<em />

Replacing:

Q = -45.00*4.184J/g°C*10.00°C

Q = -1882J

Right answer is:

<h3>D. -1882J</h3>

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7 0
2 years ago
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levacccp [35]

Answer:

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Explanation:

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JulsSmile [24]

Answer:

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