The new pH of the solution after the addition of water would be 13.22.
<h3>
Total volume of the solution</h3>
V(total) = 609 ml + 594 ml
V(total) = 1203 ml
<h3>Concentration of water </h3>
C = (594 ml)/(1203 ml)
C = 0.493
pOH = -log(0.493)
pOH = 0.31
New pH of the solution = 13.5292 - 0.31 = 13.22
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The balanced chemical reaction is:
<span>4NH3 + 6NO → 5N2 + 6H2O
</span>
We are given the amount of nitric oxide to be used in the reaction. This will be the starting point of the calculations.
27.8 g NO ( 1 mol NO / 30.01 g NO ) ( 4 mol NH3 / 6 mol NO ) ( 17.0337 g NH3 / 1 mol NH3 ) = 10.52 g NH3
Answer:
In the reaction ocurrs a nucleophilic substitution of a primary alkyl bromide, where the nucleophile is CH3O-.
Explanation:
Nucleophilic substitution is a type of substitution reaction in which a nucleophile replaces an atom or group in an electrophilic position of a molecule, called a leaving group.
It is a type of fundamental reaction in organic chemistry, where the reaction occurs on an electrophilic carbon. Although nucleophilic substitution reactions can also take place on covalent inorganic compounds.
Answer:
4.75 moles of oxygen would be consumed by water
Explanation:
Given data:
Mass of water produced = 68.1 g
Number of moles of oxygen consumed = ?
Solution:
Chemical equation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Number of moles of water:
Number of moles = mass/molar mass
Number of moles = 68.1 g/ 18 g/mol
Number of moles = 3.8 mol
Now we will compare the moles of water with oxygen.
H₂O : O₂
4 : 5
3.8 : 5/4×3.8 = 4.75 mol
Answer:
3 CO₃²⁻(aq) + 2 Cr³⁺(aq) ⇒ Cr₂(CO₃)₃(s)
Explanation:
Let's consider the molecular equation that occurs when aqueous solutions of ammonium carbonate and chromium(III) nitrate are combined.
3 (NH₄)₂CO₃(aq) + 2 Cr(NO₃)₃(aq) ⇒ 6 NH₄NO₃(aq) + Cr₂(CO₃)₃(s)
The complete ionic equation includes all the ions and insoluble species.
6 NH₄⁺(aq) + 3 CO₃²⁻(aq) + 2 Cr³⁺(aq) + 6 NO₃⁻(aq) ⇒ 6 NH₄⁺(aq) + 6 NO₃⁻(aq) + Cr₂(CO₃)₃(s)
The net ionic equation includes only the ions that participate in the reaction and the insoluble species.
3 CO₃²⁻(aq) + 2 Cr³⁺(aq) ⇒ Cr₂(CO₃)₃(s)