If we are comparing two different things to each other on Earth, they are pulled the same by gravity and so the one with more mass weighs more. But in space, where the pull of gravity is very small, something can have almost no weight. It still has matter in it, though, so it still has mass.
These types of animals are referred to as D. scavengers.
Scavenger animals are adapted to feed on dead and decaying meat and usually feed on the carcasses left over by predatory animals. An example is how vultures pick off the meat from a zebra carcass that has been left over after a lion pack has finished eating from it.
Answer:
To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law. The equation follows:
\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}
T
1
P
1
V
1
=
T
2
P
2
V
2
where,
P_1,V_1\text{ and }T_1P
1
,V
1
and T
1
are the initial pressure, volume and temperature of the gas
P_2,V_2\text{ and }T_2P
2
,V
2
and T
2
are the final pressure, volume and temperature of the gas
We are given:
\begin{gathered}P_1=760mmHg\\V_1=175L\\T_1=15^oC=[15+273]K=288K\\P_2=640mmHg\\V_2=198L\\T_2=?K\end{gathered}
P
1
=760mmHg
V
1
=175L
T
1
=15
o
C=[15+273]K=288K
P
2
=640mmHg
V
2
=198L
T
2
=?K
Putting values in above equation, we get:
\begin{gathered}\frac{760mmHg\times 175L}{288K}=\frac{640mmHg\times 198L}{T_2}\\\\T_2=274K\end{gathered}
288K
760mmHg×175L
=
T
2
640mmHg×198L
T
2
=274K
Hence, the temperature when the volume and pressure has changed is 274 K
Answer:
4.48 grams of potassium hydroxide that the chemist must be weighing out.
Explanation:
The pH of the KOH solution = 13
pH + pOH = 14
pOH = 14 - pH = 14 - 13 = 1
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
![1=-\log[OH^-]](https://tex.z-dn.net/?f=1%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=0.1 M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.1%20M)
1 mole of hydroxide ions are obtained from 1 mole of KOH. Then 0.1 mole of hydroxide ions will be obtained from :
of KOH
![[Molarity]=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}](https://tex.z-dn.net/?f=%5BMolarity%5D%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20solute%7D%7D%7B%5Ctext%7BVolume%20of%20solution%28L%29%7D%7D)
Volume of KOH solution = 800 mL = 0.800 L ( 1 mL = 0.001 L)
Moles of KOH = 0.1 M × 0.800 L = 0.08 mol
Mass of 0.08 moles of KOH :
0.08 mol × 56 g/mol = 4.48 g
4.48 grams of potassium hydroxide that the chemist must be weighing out.
Since you did not give the reactions, i cannot give the answers.
In organic and inorganic chemistry, nucleophilic substitution is a fundamental class of reactions in which an electron rich nucleophile selectively bonds with or attacks the positive or partially positive (+ve)charge of an atom or a group of atoms to replace a leaving group; the positive or partially positive atom is referred to as an electrophile. The whole molecular entity of which the electrophile and the leaving group are part is usually called the substrate.
The most general form for the reaction may be given as the following:
<span>Nuc: + R-LG → R-Nuc + LG<span>:</span></span>
