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Vlada [557]
3 years ago
8

6. The four main systems of the Earth are

Physics
2 answers:
nevsk [136]3 years ago
8 0
Geosphere, hydrosphere, atmosphere, and biosphere.

Therefore, the correct answer is D.
GuDViN [60]3 years ago
3 0

D. geosphere, atmosphere, hydrosphere, and biosphere.

You might be interested in
What magnitude charge creates a 1.0 n/c electric field at a point 1.0 m away?
Stolb23 [73]

Answer:

1.1\cdot 10^{-10}C

Explanation:

The electric field produced by a single point charge is given by:

E=k\frac{q}{r^2}

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

In this problem, we have

E = 1.0 N/C (magnitude of the electric field)

r = 1.0 m (distance from the charge)

Solving the equation for q, we find the charge:

q=\frac{Er^2}{k}=\frac{(1.0 N/c)(1.0 m)^2}{9\cdot 10^9 Nm^2c^{-2}}=1.1\cdot 10^{-10}C

8 0
3 years ago
How many earths could fit inside jupiter
Snezhnost [94]

1,300 or more.

hope this helped :)

8 0
4 years ago
To determine if an object is in motion, you must use a __________. Question 1 options: Moving object Living thing Frame of Refer
Lubov Fominskaja [6]

Answer: moving object :)

Explanation:

8 0
3 years ago
Motion maps for two objects, Y & Z, are shown.
serg [7]

Answer: it’s 3 seconds

Explanation:

5 0
2 years ago
El espectro visible en el aire está comprendido entre la longitud de onda 450 nm del color azul, Determina la velocidad de propa
TiliK225 [7]

Answer:

v = 2,99913 10⁸ m / s

Explanation:

The velocity of propagation of a wave is

         v = λ f

in the case of an electromagnetic wave in a vacuum the speed that speed of light

         v = c

When the wave reaches a material medium, it is transmitted through a resonant type process, whereby the molecules of the medium vibrate at the same frequency as the wave, as the speed of the wave decreases the only way that they remain the relationship is that the donut length changes in the material medium

         λ = λ₀ / n

where n is the index of refraction of the material medium.

Therefore the expression is

           v = \frac{\lambda_o}{n} f

Let's look for the frequency of blue light in a vacuum

           f =\frac{c }{\lambda_o}  

           f = \frac{3 \ 10^8}{450 \ 10^{-9}}

           f = 6.667 10¹⁴ Hz

the refractive index of air is tabulated

           n = 1,00029

let's calculate

           v = \frac{450 \ 10^{-9} }{1.00029}  \ 6.667 \ 10^{14}450 10-9 / 1,00029 6,667 1014

            v = 2,99913 10⁸ m / s

we can see that the decrease in speed is very small

8 0
3 years ago
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