Answer:
ΔH°rxn = -827.5 kJ
Explanation:
Let's consider the following balanced equation.
2 PbS(s) + 3 O₂(g) → 2 PbO(s) + 2 SO₂(g)
We can calculate the standard enthalpy of reaction (ΔH°rxn) from the standard enthalpies of formation (ΔH°f) using the following expression.
ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g)
)] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g)
)]
ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g)
)] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g)
)]
ΔH°rxn = [2 mol × (-217.32 kJ/mol) + 2 mol × (-296.83)] - [2 mol × (-100.4) + 3 mol × 0 kJ/mol]
ΔH°rxn = -827.5 kJ
Multiple by 2 because it was give u right answer
You would have to show me the answers
It's el mapa so the answer is incorrect. Even though mapa has an 'a' at the end, you will still use el.
Answer:
C. its particles move farther apart and the substance becomes a gas.
Explanation:
A. is wrong because moving closer together creates a solid, not a gas.
B. is wrong because moving father apart creates a gas, not solid.
C. is correct because moving farther apart creates a gas.
D. is wrong because when heat is added particles spread apart because they vibrate faster. Although, in a solid the particles are closer together.
- Just know the states of matter and how the particles move and that will help with this problem.
