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sattari [20]
2 years ago
15

Three forces act on a statue. Force F⃗ 1F→1 (magnitude 45.0 NN) points in the +x-direction, Force F⃗ 2F→2 (magnitude 105 NN) poi

nts in the +y-direction, and force F⃗ 3F→3 (magnitude 235 NN) is at an angle of 36.9∘∘ from the -x-direction and 53.1∘∘ from the +y-direction. counterclockwise from the +x-direction. Find the x- and y-components of the net external force F⃗ F→ on the statue
Physics
1 answer:
Trava [24]2 years ago
5 0

Answer:

Resultant force = (232.93î + 246.10j) N

x-component of the resultant force = (+232.93î) N

y-component of the resultant force = (+246.1j) N

Explanation:

The net external force on the statue is equal to the resultant force on the statue.

And the resuphant force is a vector sum of all the other forces acting on the statue.

Force 1 = (45î) N

Force 2 = (105j) N

Force 3 = (235cos 36.9°)î + (235 sin 36.9°)j = (187.93î + 141.10j) N

Resultant force = (Force 1) + (Force 2) + (Force 3)

Resultant force = 45î + 105j + (187.93î + 141.10j) = (232.93î + 246.10j) N

Hope this helps!!!

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Explanation:

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3 years ago
A 48-kg woman pushes a 12-kg grocery cart with a force of 24 N. What is the magnitude of the force that the grocery cart exerts
Nata [24]

The correct answer is B. 24 N.

To figure out the exact force the cart exerts on the woman, we have to use Newton's third law of motion.  Newton's third law of motion states that every action has an equal and opposite reaction. This means that if object  1 exerts a force on object 2 , object 2 will exert an equal but opposite force on object 1.

This law allows us to ignore the masses of the chart and the women and focus on the  pairs of forces the woman and the chart apply to each other.  Since the woman exerts a force of 24 N on the chart, the chart will exert a force of 24 N on the woman.

The correct answer is B. 24 N.

4 0
3 years ago
A ball is thrown with a speed of 20 m/s at an angle of 40o above the horizontal from the top of a 22-m tall building.
MrRissso [65]

Answer:

(a). The distance is  49.79 m.

(b). The speed of the ball is 24.39 m/s.

Explanation:

Given that,

Speed = 20 m/s

Angle = 40°

Height = 22 m

Time = 3.25 sec

(a). We need to calculate the distance

Using formula of distance

d=u\cos\theta\times t

Put the value into the formula

d=20\cos40\times3.25

d=49.79\ m

(b). We need to calculate the horizontal velocity

Using formula of velocity

v_{x}=u\cos\theta

Put the value into the formula

v_{x}=20\times\cos40

v_{x}=15.3\ m/s

We need to calculate the vertical velocity

Using equation of motion

v_{y}=u\sin\theta-gt

Put the value into the formula

v_{y}=20\sin40-9.8\times3.25

v_{y}=-19\ m/s

Negative sign shows the opposite direction.

We need to calculate the speed of ball

Using formula of speed

v=\sqrt{v_{x}^2+v_{y}^2}

v=\sqrt{(15.3)^2+(19)^2}

v=24.39\ m/s

Hence, (a). The distance is  49.79 m.

(b). The speed of the ball is 24.39 m/s.

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2 years ago
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Correct answer choice is:

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