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Stells [14]
2 years ago
12

2. FAt=p (remember p=mv). A 2.5Jg baseball moving at 8.5m/s to the left is slowed by a tipped

Physics
1 answer:
TiliK225 [7]2 years ago
3 0

The force of the tripped catch exerted on the 2.5 Kg ball moving at 8.5 m/s to the Left is 160 N

<h3>Data obtained from the question </h3>
  • Initial velocity (u) = 8.5 m/s
  • Final velocity (v) = 7.5 m/s
  • Time (t) = 5 ms = 0.25 s
  • Mass (m) = 2.5 Kg
  • Force (F) = ?

<h3>How to determine the force</h3>

The force exerted on the ball can be obtained as follow:

F = m(v + u) / t

F = [2.5(7.5 + 8.5)]/ 0.25

F = 40 / 0.25

F = 160 N

Thus, the force exerted on the ball is 160 N

Learn more about momentum:

brainly.com/question/250648

#SPJ1

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A box sliding on a horizontal frictionless surface encounters a spring attached to a rigid wall and compresses the spring by a c
GaryK [48]

Answer:

a) K = 49.5 J  b) k = 1378 N / m c) ΔE = 34 J  d)  μ = 0.399

Explanation:

For this exercise we will use the concepts of energy

a) The initial kinetic energy is

    K = ½ m v²

    K = ½ 3.96 5²

    K = 49.5 J

b) let's use energy conservation

    Em₀ = K = ½ m v²

    Em_{f} = Ke = ½ k x²

    Em₀ =  Em_{f}

    ½ m v² = ½ k x²

    k = m v² / x²

    k = 3.96 5² / 0.268²

    k = 1378 N / m

c) Let's calculate the final energy of the spring

     Em_{f} = Ke = ½ k x²

    Em_{f} = ½ 1378 0.15²

     Em_{f} = 15.5 J

The initial energy is the kinetics of the block

    Em₀ = 49.5 J

The lost energy is the difference with the initial

    ΔE =  Em_{f} - Em₀

    ΔE = 15.5 - 49.5

    ΔE = - 34 J

the negative sign means that the energy dissipates

d) For this part we use the concept of work

   W = F d cos θ = ΔK

In this case the force is the friction force that always opposes displacement, so the angle 180 ° and cos 180 = -1

    W = -fr d = ΔK

The force of friction is

   fr = μ N

With Newton's second law

    N-w = 0

    N = W = mg

Let's calculate

   -μ mg d = Kf -K₀o

    μ = K₀ / mgd

    μ = 49.5 / (3.96  9.8  3.20)

    μ = 0.399

8 0
3 years ago
The speed of a wave with a frequency of 2 Hz (2/s), an amplitude of 3 m, and a wavelength of 10 m is
Inessa05 [86]

Answer:

5 m/s

Explanation:

your welcome

6 0
2 years ago
A bike with tires of radius 0.330 m speeds up from rest to 5.33 m/s in 6.27 s. What is the angular acceleration of the tires?
Nimfa-mama [501]

The angular acceleration of a bike with tires of radius 0.330 m speeds up from rest to 5.33 m/s in 6.27 s will be 2. 57 rad/s²

<h3>What is angular acceleration?</h3>

Angular acceleration can be defined as the time it takes for a change in angular velocity. It is denoted as 'α' with a unit of rads/s²

It is expressed thus;

α= Δω ÷ Δt

Where α = angular acceleration

Δw = change in angular velocity = velocity ÷ radius

Δ t = change in time

<h3>How to calculate the angular acceleration</h3>

Using the formula:

α= Δω ÷ Δt

v = 5. 33m/s, r = 0. 33m and t = 6.27s

Substitute the values to get the angular velocity

Δw = v÷ r = 5. 33 ÷ 0.330 = 16. 15 m/s

Substitute the value of Δw into the equation

α= Δω ÷ Δt = 16. 15 ÷ 6. 27 = 2. 57 rad/s²

Therefore, the angular acceleration of a bike with tires radius of 0. 330m, speed of 5. 33mls in 6. 27s is 2. 57 rad/s²

Learn more about angular acceleration here:

brainly.com/question/21278452

#SPJ1

8 0
1 year ago
Truck drivers approaching a steep hill that they must climb often increase their speed. What good does this do, if any?
Inga [223]
Um, this doesn't make any sense. By climbing a hill, you are decreasing your momentum and kinetic energy, so it slows you down. The only positive, is after you have climbed the hill, you have more potential energy, and it will be released once you go down the hill, but you will not be as fast as if you ignored the hill.
6 0
2 years ago
How far away is the closest star?
sukhopar [10]

Answer: Proxima Centauri is the closet star about 40,208,000,000,000 km away. 

Explanation:

8 0
1 year ago
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