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alex41 [277]
3 years ago
14

The period of a pendulum may be decreased by

Physics
2 answers:
jok3333 [9.3K]3 years ago
8 0

Answer:

shortening its length.

zheka24 [161]3 years ago
8 0

Answer:

shortening jshshdjskai

usbeeduene

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Two asteroids identical to those above collide at right angles and stick together; i.e, their initial velocities were perpendicu
11111nata11111 [884]

Answer:

velocity = 62.89 m/s  in 58 degree measured from the x-axis

Explanation:

Relevant information:

Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.

Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.

Before collision Momentum of A = 1000 x 100 = $ 10^5$ kg - m/s in the right direction.

Before collision Momentum of B = 2000 x 80 = 1.6 x $ 10^5$  kg - m/s in upward direction.

Mass of System of after collision = 1000 + 2000 = 3000 kg

Now applying the Momentum Conservation, we get

Initial momentum in right direction = final momentum in right direction = $ 10^5$

And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x $ 10^5$

So, $ V_x = \frac{10^5}{3000} $  = $ \frac{100}{3} $  m/s

and $ V_y=\frac{160}{3}$  m/s

Therefore, velocity is = $ \sqrt{V_x^2 + V_y^2} $

                                   = $ \sqrt{(\frac{100}{3})^2 + (\frac{160}{3})^2} $

                                   = 62.89 m/s

And direction is

tan θ = $ \frac{V_y}{V_x}$     = 1.6

therefore, $ \theta = \tan^{-1}1.6 $

                   = $ 58 ^{\circ}$  from x-axis

4 0
3 years ago
How do you make a mirages?​
Aleksandr [31]

Answer:

when the ground is very hot and the air is cool.

Explanation:

The hot earth warms a layer of air right above the ground. Light is refracted as it passes through the cool air and onto the hot air sheet (bent). A coating of very warm air near the earth bends the light from the sky almost into a U-shaped bend.

7 0
3 years ago
Read 2 more answers
Determine the field strength, E, experienced by a test charge, q, if a charge of 7.0 × 10-5 coulombs is placed on q and a force
kkurt [141]
Formula for feild strength= F/q
q=7.0^10-5 coulombs
F=5.2 N
E=5.2 / 7.0^10-5
E=
7 0
3 years ago
Read 2 more answers
PLEASE HELP. I WILL MARK BRAINIEST
anyanavicka [17]
Aaaaaaaaaaaaaaaaaaaaaaaa
6 0
3 years ago
Boxes are transported from one location to another in a warehouse by means of a conveyor belt that moves with a constant speed o
krek1111 [17]

Answer:

P = 15.90 W

Explanation:

given,

speed of conveyor belt = 0.56 m/s

conveyor belt move up to = 2 m      

angle made with the horizontal = 15°

mass of the box = 2.1 kg                      

rate is the force of the conveyor belt doing work on the box as the box moves up                                                  

P = F v cos ∅

P = 3 × 9.8 × 0.56 × cos 15°

P = 15.90 W

6 0
3 years ago
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