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Angelina_Jolie [31]
3 years ago
9

a student moves a box across the floor by exerting 23.3 N of force and doing 47.2 J of work on the box. How far does the student

move the box?
Physics
1 answer:
kozerog [31]3 years ago
8 0
Work = Force x Distance
47.2J = 23.3N x d
d = 47.2/23.3
d = 2.0258 m

hope this helps :P
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Answer:

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Explanation:

Initially the ball is at rest, u = 0

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H=ut+\dfrac{1}{2}at^2

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<em>B) 1.0 × 10^5 V</em>

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The electric potential produced from a point charge Q at a distance r from the charge is

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We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

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Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of \pm 3\mu\ C. Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

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V_1=V_2=50912\ V

The total potential is

V_t=50912\ V+50912\ V=1\times 10^5\ V

\boxed{V_t=1\times 10^5\ V}

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