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Kobotan [32]
3 years ago
14

TP-10 Which of the following is considered a safe refueling practice?

Physics
1 answer:
erik [133]3 years ago
7 0

Answer:

The correct option is;

Sending all passengers below while refueling

Explanation:

Safety tips for refueling a boat includes;

1) People that are not involved in the refueling of the boat should be made to leave the area

2) The engines, electronics, ignition system and open flames should be off

3) Ensure the boat is properly secured to the dock

4) Do not use the hands-free clips and try not to be distracted

5) Ensure not to completely fill the fuel tank as fuel has the tendency to expand as its temperature rises. The tank should have about 90% filling

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An unknown additional charge q3q3q_3 is now placed at point B, located at coordinates (0 mm, 15.0 mm ). Find the magnitude and s
Yanka [14]

Answer:

0.3nanocouloumb

Explanation:

Pls see attached file

7 0
4 years ago
A 0.60-kilogram softball initially at rest is hit with a bat. The ball is in contact with the bat for 0.20 second and leaves the
Furkat [3]

Answer:

75 Newtons.

Explanation:

From Newton's second law of motion,

F = m(v-u)/t................... Equation 1

Where F = force exerted by the ball on the bat, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time

Given: m = 0.6 kilogram, u = 0 meter per seconds (at rest), v = 25 meters per seconds, t = 0.2 seconds.

Substitute into equation 1

F = 0.6(25-0)/0.2

F = 3(25)

F = 75 Newton.

Hence the magnitude of the average force exerted by the ball on the bat = 75 Newtons.

8 0
4 years ago
PLEASE HELP!! I'll mark brainliest for correct answer.
Tju [1.3M]
1. Car A
2. Car C
3. Car A
4. 1500 J
5. 750 J
6. 750 J
7. Car A was had a height higher relative to the ground compared to all the other cars.
8. mgh
9. B
6 0
3 years ago
Monochromatic light falls on two very narrow slits 0.047 mm apart. Successive fringes on a screen 6.60 m away are 8.9 cm apart n
Svet_ta [14]

Answer::

   \lambda  =  634 nm

  f =  4.73 *10^{14} \  Hz

Explanation:

From the question we are told that

      The  distance of separation is  d =  0.047 \ mm =  0.047 *10^{-3} \ m

       The  distance of the screen is  D =  6.60 \ m

      The  width of the fringe is y  =  8.9 \ cm  =  0.089 \ m

     

Generally the width of the width of the fringes is mathematically represented as

          y  = \frac{\lambda  *  D }{d }

=>       \lambda  =  \frac{y *  d }{D }

=>      \lambda  =  \frac{ 0.089  *   (0.047 *10^{-3}) }{6.60  }

=>    \lambda  =  634 *10^{-9}

=>  \lambda  =  634 nm

Generally the speed of light is mathematically represented as

         c  =  f * \lambda

=>       f=  \frac{ c}{\lambda }

=>         f=  \frac{ 3.0 *10^{8}}{634 *10^{-9}}

=>     f =  4.73 *10^{14} \  Hz

6 0
3 years ago
Write a letter to ur mother living in
Westkost [7]

Answer:

no....

Explanation:

5 0
3 years ago
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