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Anastaziya [24]
3 years ago
10

Why a raw egg shell disolves when submerge in vineger

Physics
2 answers:
quester [9]3 years ago
6 0
If you soak this egg shell in vinegar (which is about 4% acetic acid), you start a chemical reaction that dissolves the calcium carbonate shell. The acetic acid reacts with the calcium carbonate in the egg shell and releases carbon dioxide gas that you see as bubbles on the shell.
fredd [130]3 years ago
5 0

Because of the acid inside of it.

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A fireperson is 50 m from a burning building and directs a stream of water from a fire hose at an angle of 300 above the horizon
notsponge [240]

Answer:

We can think the water stream as a solid object that is fired.

The distance between the fireperson and the building is 50m. (i consider that the position of the fireperson is our position = 0)

The angle is 30 above the horizontal. (yo wrote 300, but this has no sense because 300° implies that he is pointing to the ground).

The initial speed of the stream is 40m/s.

First, using the fact that:

x = R*cos(θ)

y = R*sin(θ)

in this case R = 40m/s and θ = 30°

We can use the above relation to find the components of the velocity:

Vx = 40m/s*cos(30°) = 34.64m/s

Vy = 20m/s.

First step:

We want to find the time needed to the stream to hit the buildin.

The horizontal speed is 34.64m/s and the distance to the wall is 50m

So we want that:

34.64m/s*t = 50m

t = 50m/(34.64m/s) = 1.44 seconds.

Now we need to calculate the height of the stream at t = 1.44s

Second step:

The only force acting on the water is the gravitational one, so the acceleration of the stream is:

a(t) = -g.

g = -9.8m/s^2

For the speed, we integrate over time and we get:

v(t) = -g*t + v0

where v0 is the initial speed: v0 = 20m/s.

The velocity equation is:

v(t) = -g*t + 20m/s.

For the position, we integrate again over time:

p(t) = -(1/2)*g*t^2 + 20m/s*t + p0

p0 is the initial height of the stream, this data is not known.

Now, the height at the time t = 1.44s is

p(1.44s) = -5.9m/s^2*(1.44s)^2 + 20m/s*1.44s + po

             = 16.57m + p0

So the height at wich the stream hits the building is 16.57 meters above the initial height of the fire hose.

5 0
3 years ago
Please help with this problem. Thank you.​
4vir4ik [10]

Answer:

Explanation:

F = mω²R

F = 15(2π/8.5)²(7.8)

F = 63.93044788...

F = 63.9 N

answer a) is the closest. No idea how they got a value that low unless they used a poor approximation for π.

4 0
3 years ago
Two stars that are in the same constellation:
Burka [1]

Answer:

Option (3)

Explanation:

A constellation is usually defined as a collection of stars that appears in the sky forming a particular type of shape or pattern. They are located at a very large distance from one another. These constellations are often used in order to locate any astronomical objects in space.

These stars appearing in a constellation generally appears to be closer to one another in the night sky, but they are actually located at about many light years away from one another.  

For example, in the Orion constellation, the stars appearing in the sky are about 25-30 light-years away from one another.

Thus, the correct answer is option (3).

7 0
3 years ago
A thin film of oil (n = 1.27) is located on smooth, wet pavement. When viewed from a direction perpendicular to the pavement, th
alisha [4.7K]

Answer:

Explanation:

The problem is based on interference in thin films

refractive index of water is more than given oil so there will be phase change of π at upper and lower layer of the film .

a )

for constructive interference , the condition is

2μt = nλ where t is thickness of layer , μ is refractive index , λ is wavelength and n is order of the fringe

Putting the values

2 x 1.27 t = n x 640

2 x 1.27 t =  640 ( for minimum thickness n = 1 )

t = 252 nm .

b )

2 x 1.27 t = m₁  λ₁

for destructive interference

2μt = (2m₂+1)λ₂/2

2 x 1.27 t =(2m₂+1)λ₂/2

m₁ λ₁  = (2m₂+1)λ₂/2

2m₁λ₁  = (2m₂+1)λ₂

2m₁ / (2m₂+1) = λ₂ / λ₁

2m₁ / (2m₂+1) = 548/ 640

2m₁ / (2m₂+1) = .85625

2m₁ = .85625 (2m₂+1)

This is the required relation between m₁ and m₂

6 0
3 years ago
Mention two ways to increase the strength of an electro magnet.
VikaD [51]

1.) Law of Induction.

2.) Increase Winding Count

6 0
3 years ago
Read 2 more answers
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