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bazaltina [42]
3 years ago
9

Help !!!!!!!!Please its Urgent.​

Physics
1 answer:
Wewaii [24]3 years ago
6 0

None can.

A clinical thermometer only measures temperatures above +30°C.

Mercury and alcohol are both frozen solid at -50°C.

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A neutral atom possesses an atomic number of 13 and an atomic mass of 27. Three electrons are lost. From what region of the atom
slega [8]
The atomic number of the atom is 13. This means that its electronic configuration is (2 8 3) or in other words:
1<span>s2, </span>2<span>s2, </span>2<span>p6, </span>3<span>s2, </span>3<span>p<span>1

If three electrons are lost, then these electrons are removed from the outermost level.
In our case, electrons are removed from the third energy level (one electron is removed from the 3p orbital and two electrons are removed from the 3s orbital).</span></span>
8 0
3 years ago
A car travelled 60 km west in 1.33 h along a straight line, then returned back east for 40 km in 0.67 h. Its average velocity is
Sholpan [36]

Answer:

Option A

Explanation:

Velocity is expressed as distance covered per unit time, with respect to direction. Therefore, v=d/t

Given distance west as 60 km and time as 1.33 then velocity will be

V=60/1.33=45.112781954887 km/h

Rounded off as 45.11 km/h West

Velocity in East will also be given by substituting 40 km for d and 0.67 h for h hence

V=40/0.67=59.701492537313 km/h rounded off as 59.70 km/h East

Taking East as positive then West as negative, the sum of two velocities will be (59.70+-45.11)/2=7.295 km/h East

Approximately 10 km/h East since it is positive

7 0
3 years ago
A train is moving along a track with constant speed v1 relative to the ground. A person on the train holds a ball of mass m and
scoundrel [369]

Answer:

(a)0.5m(2v1v2+v2^{2})\\(b)0.5m(v2^{2}-v1^{2})\\(c)0.5m(2v1v2+v2^{2})\\(d)0.5m(v2^{2}-v1^{2})

Explanation:

velocity of ball in train reference = v2

velocity of ball in earth reference = v1+v2

(a)

Kinetic energy is given by 0.5mv^{2} where m and v are the mass and velocity of object respectively.

Change in kinetic energy is given by subtracting initial kinetic energy from the final kinetic energy. In this case

Initial kinetic energy= 0.5mv1^{2}

Final kinetic energy= 0.5m (v1+v2)^{2}=0.5m(v1^{2}+2v1v2+v2^{2})

Change in kinetic energy=0.5m (v1+v2)^{2}-0.5mv1^{2}=0.5m((v1+v2)^{2})-v1^{2}=0.5m(2v1v2+v2^{2}

(b)

Change in velocity in train reference will be

Initial kinetic energy= 0.5mv1^{2}

Final kinetic energy= 0.5mv2^{2}

Change in kinetic energy=0.5m(v2^{2}-v1^{2})

(c)

Work done, W = change in kinetic energy=0.5m (v1+v2)^{2}-0.5mv1^{2}=0.5m((v1+v2)^{2})-v1^{2}=0.5m(2v1v2+v2^{2}

(d)

Work done, W = change in kinetic energy=0.5m(v2^{2}-v1^{2})

4 0
3 years ago
A thermosensory neuron in the skin converts heat energy to nerve impulses via a conversion called
Sav [38]

Answer:

Sensory transduction

Explanation:

The term sensory transduction refers to the conversion process where the sensory energy is converted in order to change the potential of a membrane.

In other words, it can defined as the process of energy conversion such that stimulus can be transmitted or received by the sensory receptors and the nervous system may initiate with the sensory receptors.

Transduction takes in all of the five receptors of the body. Thus skin is also one of the receptors and hence conversion of heat energy into impulses takes place with the help of thermo-sensory neuron.

3 0
3 years ago
While visiting the Albert Michelson exhibit at Clark University, you notice that a chandelier (which looks remarkably like a sim
Fudgin [204]

Answer:

a) 0,1613 Hz

b) 1,01342 rad/sec

c) 9.5422 m

d) 9.4314 m/sec^2

Explanation:

In the Albert Michelson exhibit at Clark University, we know the period of oscillation of the chandelier is T = 6.2 seconds

The chandelier will be modeled as a simple pendulum

a) Since the frequency is the reciprocal of the period, we have

f=\frac{1}{T}=\frac{1}{6.2sec}=0,1613 Hz

b) The angular frequency is computed as

w=2\pi f=2\pi (0,1613) = 1,01342\ rad/sec

c) The period of a simple pendulum is given by

T=2\pi \sqrt{\frac{L}{g}}

Where L is its length and g is the local acceleration of gravity (assumed 9.8 m/sec^2 for this part)

We want to know the length of the pendulum, so we isolate L

L=\frac{T^2g}{4\pi^2}

L=\frac{(6.2)^2(9.8))}{4\pi^2}=9.5422 m

d) While hanging out in J.J. Thompson’s House O’ Blues, the new period is 6.2+0.11=6.32 sec. Since the chandelier is the very same (same length), we can assume the gravity is slightly different. We use again the formula for T, but now we'll isolate g as follows

g=\frac{4\pi^2L}{T^2}=\frac{4\pi^2(9.5422m))}{(6.32sec)^2}

Which results  

g=9.4314\ m/sec^2

8 0
4 years ago
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