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Sergio [31]
3 years ago
7

PLEASE HELP ASAP!!!!!!!1

Physics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0

Age of dino: Mesozoic era

End of earth a dessert: End of the Mesozoic

a layer: Paleozoic

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A certain field line diagram illustrates the electric field due to three particles that carry charges 5.0 μC, -3.0 μC, and -2.0
4vir4ik [10]

Answer:

6

Explanation:

Number of lines emanate from + 5 micro coulomb is 15 .

They terminates at negative charges that means at - 3 micro coulomb and - 2 micro Coulomb.

the electric field lines terminates at - 3 micro Coulomb and - 2 micro Coulomb is in the ratio of 3 : 2.

So the lines terminating at - 3 micro coulomb

                                    = \frac{3}{5}\times 15 = 9

So the lines terminating at - 2 micro coulomb

                                    = \frac{2}{5}\times 15 = 6

So, the number of filed lines terminates at - 2 micro Coulomb are 6.

4 0
3 years ago
Exercise can help prevent?
Sedaia [141]

health conditions and diseases


8 0
3 years ago
Read 2 more answers
HELP
rusak2 [61]

Answer:

H₂0_{(s)}  +  heat  →  H₂O(l)  

Explanation:

An ENDOTHERMIC reaction is a chemical reaction in which heat is absorbed by the reactants. As such the product is usually cooler than the products. In the equation above (the answer), heat is on the reactant side of the equation thus indicating that heat is absorbed by the reactants.

On the other hand, in the first equation heat is on the product side of the equation which is consistent with an Exothermic reaction.

Have a good day♥

4 0
2 years ago
A cricket starts at the 5 meter mark on a ruler. It jumps to the 10 meter mark. Then, it jumps back to the 6 meter mark. Calcula
belka [17]

We have that the cricket’s displacement is  

D_t=9meters

From the Question we are told that

Start position  5 meter mark

It jumps to the 10 meter mark.

it jumps back to the 6 meter mark.

Generally the equation for cricket’s displacement. is mathematically given as

D_t=Initial +final(displacement)\\\\D_t=(10-5)+(10-6)

D_t=9meters

For more information on this visit

brainly.com/question/24273210?referrer=searchResults

4 0
2 years ago
What is the stopping distance if the car is initially traveling at speed 6.0v? assume that the acceleration due to the braking i
Sunny_sXe [5.5K]
The distance for any rectilinear motion at constant acceleration is:

d = v₀t + 0.5at²
where
v₀ is the initial velocity

So, if v₀ = 6v, and it stopped to 0 m/s, then the acceleration is equal to:
a = (0 - 6v)/t = -6v/t
Thus,
d = (6v)(t) + (0.5)(-6v/t)(t²)
d = 6vt - 3t
<span>d = 3t(2v - 1)</span>
4 0
3 years ago
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