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Answer:
planet that is farthest away is planet X
kepler's third law
Explanation:
For this exercise we can use Kepler's third law which is an application of Newton's second law to the case of the orbits of the planets
T² = ( a³ = K_s a³
Let's apply this equation to our case
a =
for this particular exercise it is not necessary to reduce the period to seconds
Plant W
10² = K_s
a_w =
a_w = 4.64
Planet X
a_x =
a_x = \frac{1}{ \sqrt[3]{K_s} } 74.3
Planet Y
a_y =
a_y = \frac{1}{ \sqrt[3]{K_s} } 18.6
Planet z
a_z =
a_z = \frac{1}{ \sqrt[3]{K_s} } 41.8
From the previous results we see that planet that is farthest away is planet X
where we have used kepler's third law