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Maru [420]
3 years ago
12

Plz help me I Am timed plz

Chemistry
1 answer:
nexus9112 [7]3 years ago
3 0

Answer:

D) Trees

Explanation:

I'm sure its trees, because once you cut all trees you cant regenerate, or replenish them. hope im right, sorry of its wrong!!

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Most elements are _____? <br><br> nonmetals <br> metalloids<br> metals
NARA [144]

Answer:Most elements on the periodic table are metals. Looking at the periodic table shows that most elements are metallic.

Explanation: Sorry if this want what you were looking for

4 0
2 years ago
Name four products of incomplete combustion<br><br> 1 - ____<br> 2 -____<br> 3 -____<br> 4 -_____
faltersainse [42]

Answer:

Carbon Monoxide / Carbon Dioxide / Sulfur  and Nitrogen Dioxide

Explanation:

3 0
3 years ago
What two types of particles exist within an atomic nucleus?
MissTica
Protons and Neutrons, the electrons circle around the nucleus.
Hope this Helps!
6 0
4 years ago
What is the molecular formula of the structure below?
taurus [48]

Answer:

C₆H₆

Explanation:

Each border of the figure represents 1 atom of carbon. We have 6 borders = 6 atoms of carbon.

Each atom of carbon form 4 bonds. All the carbons are doing a double bond and a single bond with other carbons. That means are bonded 3 times. The other bond (That is not represented in the figure. See the image) comes from hydrogens. As we have 6 carbons that are bonded each 1 with one hydrogen. There are six hydrogens and the molecular formula is:

<h3>C₆H₆</h3>

This structure is: Benzene

8 0
3 years ago
How many grams of oxygen (O) are present in 0.0207 moles of Ca(HCO 3) 2
Zolol [24]

Answer:

1.99grams

Explanation:

- First, we need to calculate the molar mass of the compound: Ca(HCO3)2

Ca = 40g/mol, H = 1g/mol, C = 12g/mol, O = 16g/mol

Hence, Ca(HCO3)2

= 40 + {1 + 12 + 16(3)}2

= 40 + {13 + 48}2

= 40 + {61}2

= 40 + 122

= 162g/mol

Molar mass of Ca(HCO3)2 = 162g/mol

- Next, we calculate the mass of oxygen in one mole of the compound, Ca(HCO3)2.

Oxygen = {16(3)}2

= 48 × 2

= 96g of Oxygen

- Next, we calculate the percentage composition of oxygen by mass by dividing the mass of oxygen in the compound by the molar mass of the compound i.e.

% composition of O = 96/162 × 100

= 0.5926 × 100

= 59.26%.

- The number of moles of the compound, Ca(HCO3)2, must be converted to mass by using the formula; mole = mass/molar mass

0.0207 = mass/162

Mass = 162 × 0.0207

Mass = 3.353grams

However, in every gram of Ca(HCO3)2, there is 0.5926 g of oxygen

Hence, in 3.353grams of Ca(HCO3)2, there will be;

0.5926 × 3.353

= 1.986

= 1.99grams.

Therefore, there is 1.99grams of Oxygen in 0.0207 moles (3.353g) of Ca(HCO3)2.

5 0
3 years ago
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