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Vlada [557]
3 years ago
6

The quality of ____ opposes the flow of electric current through a material .

Physics
2 answers:
Natali [406]3 years ago
4 0
I'd have to go with resistance.
QveST [7]3 years ago
3 0
The answer is Resistance
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If a sound is 30 dB and its absolute pressure was 66 x 10-9 Pa, what must have been the reference pressure?
Ksenya-84 [330]

Given:

I = 30dB

P = 66 × 10^{-9} Pa

Solution:

Formula used:

I = 20\log_{10}(\frac{P}{P_{o}})           (1)

where,

I = intensity of sound

P = absolute pressure

P_{o} = reference pressure

Using Eqn (1), we get:

30 = 20\log _{10}\frac{66\times 10^{-9}}{P^{o}}

P_{o} = \frac{66\times 10^{-9}}{10^{1.5}}

P_{o} = 2.08 × 10^{-9} Pa

4 0
4 years ago
How do unicellular organisms reproduce?
mars1129 [50]

Answer:

A

Explanation:

:)

7 0
3 years ago
You wash the dishes. when you let the water down the drain, where is the water flowing the fastest?
Goshia [24]
The water flows the fastest at the center.

This is due to the friction between the water and the sink/drain. The outer parts of the water that are in contact with the kitchen sink/drain experience a greater frictional force and slow down. Their slowing down also affects the layers of water molecules adjacent to them, thereby reducing their speed as well. The layer of water molecules least affected by the friction with the sink/drain is at the center, and so they are the ones that move the fastest.
3 0
3 years ago
The latent heat of fusion of alcohol is 50 kcal/kg and its melting point is -54oC. It has a specific heat of 0.60 in its liquid
sashaice [31]

Answer:

C

Explanation:

To melt the alcohol

Heat needed = M . L  = 2 . 25  = 50 kcal

To warm up the alcohol

Heat needed = M . sp. ht. . ∆t   = 2 . 0.6 . 100  = 120 kcal

Total heat needed = 170 kcal

Assuming that 0.6 kcal/ kg / ˚C  is the specific heat and that the answer is wanted in kcal ( a rather odd unit to be in use here.)

5 0
3 years ago
A spherical conductor with a radius of 65.7 cm has an electric field of magnitude 7.20 × 105 V/m just outside its surface. What
Paul [167]

Answer:

4.73V

Explanation:

Parameters given:

Radius of sphere = 65.7 cm = 0.657 m

Electric field = 7.2 * 10^5 V/m

Electric potential, V, is given in terms of Electric field as:

V = E * r

Where r = distance between charge and point of consideration.

Since we are considering a point just outside the spherical conductor:

V = 7.2 * 10^5 * 0.657

V = 4.73V

4 0
3 years ago
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