Answer:
the first one is D
Explanation:
so if the others u put are right the the second would be c
Answer:
2.5 * 10^-3
Explanation:
<u>solution:</u>
The simplest solution is obtained if we assume that this is a two-dimensional steady flow, since in that case there are no dependencies upon the z coordinate or time t. Also, we will assume that there are no additional arbitrary purely x dependent functions f (x) in the velocity component v. The continuity equation for a two-dimensional in compressible flow states:
<em>δu/δx+δv/δy=0</em>
so that:
<em>δv/δy= -δu/δx</em>
Now, since u = Uy/δ, where δ = cx^1/2, we have that:
<em>u=U*y/cx^1/2</em>
and we obtain:
<em>δv/δy=U*y/2cx^3/2</em>
The last equation can be integrated to obtain (while also using the condition of simplest solution - no z or t dependence, and no additional arbitrary functions of x):
v=∫δv/δy(dy)=U*y/4cx^1/2
=y/x*(U*y/4cx^1/2)
=u*y/4x
which is exactly what we needed to demonstrate.
Also, using u = U*y/δ in the last equation we can obtain:
v/U=u*y/4*U*x
=y^2/4*δ*x
which obviously attains its maximum value for the which is y = δ (boundary-layer edge). So, finally:
(v/U)_max=δ^2/4δx
=δ/4x
=2.5 * 10^-3
Christian made 1000 pancakes.
Explanation:
Let us represent the total amount of Pancake made by Christian as = K
From the problem;
Christian ate 
of the pancake in the morning = * K = K
We know that Christian cannot eat her pancake and at the same time have it, the remaining pancake will then be:
total amount of cake - fraction eaten
Remainder = K - K= 
K
In the afternoon, we know that she ate 1/4 of the remaining cake:
K* K = 
K
The remaining cake in the afternoon will be:
Total amount of cake remaining from morning - amount eaten in the afternoon
= K - K
= 
K
The fraction of the cake remaining in the afternoon is K
Since she had 300cakes left in the afternoon, then :
K= 300
K = 1000 pancakes
Therefore Christian made 1000 pancakes.
learn more:
Fractions brainly.com/question/1648978
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Specific heat. The definition of specific heat is the amount of energy required to raise the temperature of 1g of a substance by 1K or 1°C.
