3 years ago

This is due today, someone pls help!

2 answers:

Alex3 years ago

6 0

The answer should be 32,890!

Move the decimal 4 places to the right
3.289 —> 32890

Jesse moved it 7 places to the right!

I’m not great at explaining but I hope it’ll help!

Juli2301 [7.4K]3 years ago

3 0

The answer to this should be 32,890

You might be interested in

A 5 in x 7 in picture is in a frame of uniform width x. The area of the picture and the frame together is 99 in How wide is the

pantera1 [17]

35..........................

8 0

3 years ago

Mica is solving for the zeros of a quadratic function by

STALIN [3.7K]

Answer: the answer is B

Step-by-step explanation:

it’s on edge

5 0

3 years ago

Read 2 more answers

Todor was trying to factor 10x^2-5x+15. He found that the greatest common factor of these terms was 5 and made an area model: Wh

jenyasd209 [6]

Answer:

The width of the area model is equal to

$(2x^2-x+3)\ units$

Step-by-step explanation:

we know that

The area of a rectangular model is given by the formula

$A=LW$ ----> equation A

where

L is the length

W is the width

we have

$A=10x^2-5x+15$

Factor the expression

$A=5(2x^2-x+3)$

substitute the value of the Area in the equation A

$5(2x^2-x+3)=LW$

In this problem

The greatest common factor of these terms is the length (L=5 units)

we can say that the width is equal to (2x^2-x+3)

therefore

The width of the area model is equal to

$(2x^2-x+3)\ units$

4 0

3 years ago

Joel wants to find the best model for a bivariate data set that he is working with. He used a calculator to create a linear mode

laiz [17]

Answer:

exponential

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the circumference of a circle whose area is 24 pi ft ^2

lianna [129]

$\bf \textit{area of a circle}\\\\
A=\pi r^2~~
\begin{cases}
r=radius\\
-----\\
A=24\pi 
\end{cases}\implies 24\pi =\pi r^2\implies \cfrac{24\pi }{\pi }=r^2
\\\\\\
24=r^2\implies \boxed{\sqrt{24}=r}\\\\
-------------------------------\\\\
\textit{circumference of a circle}\\\\
C=2\pi r\qquad \qquad \implies C=2\pi\left( \boxed{\sqrt{24}} \right)~~
\begin{cases}
24=2\cdot 2\cdot 2\cdot 3\\
\qquad 2^2\cdot 6
\end{cases}
\\\\\\
C=2\pi \sqrt{2^2\cdot 6}\implies C=2\pi (2\sqrt{6})\implies C=4\sqrt{6}~\pi$

3 0

4 years ago