1/3-2/9
=3/9-2/9 Multiply 1/3 by 3/3 (1) to get common denominator to subtract
=1/9
It will be whichever equation you see that has the "c" = +3, in the format:
F(x) = y = ax^2 + bx + c, where a, b, and c are all integers, such that plugging a "0" into the x's will give:
y = a•0^2 + b•0 + 3 = 0 + 0 + 3 = 3
You haven't included enough information for the question, but assuming that a and b are the same then a is 4 and b is 4
Answer:
id.k but i need points sorry
Step-by-step explanation:
Answer:
a) 0.50575,
b) 0.042
Step-by-step explanation:
Example 1.5. A person goes shopping 3 times. The probability of buying a good product for the first time is 0.7.
If the first time you can buy good products, the next time you can buy good products is 0.85; (I interpret this as, if you buy a good product, then the next time you buy a good product is 0.85).
And if the last time I bought a bad product, the next time I bought a good one is 0.6. Calculate the probability that:
a) All three times the person bought good goods.
P(Good on 1st shopping event AND Good on 2nd shopping event AND Good on 3rd shopping event) =
P(Good on 1st shopping event) *P(Good on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st and 2nd shopping events yield Good) =
(0.7)(0.85)(0.85) =
0.50575
b) Only the second time that person buys a bad product.
P(Good on 1st shopping event AND Bad on 2nd shopping event AND Good on 3rd shopping event) =
P(Good on 1st shopping event) *P(Bad on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st is Good and 2nd is Bad shopping events) =
(0.7)(1-0.85)(1-0.6) =
(0.7)(0.15)(0.4) =
0.042
