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Lesechka [4]
2 years ago
8

How many pairs of autosomal chromosomes does each person without chromosomal abnormalities have?

Chemistry
1 answer:
enot [183]2 years ago
6 0
C. 23 pairs

There are a total of 46 chromosomes
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On a caterpillar's map, all distances are marked in millimeters. The caterpillar's map shows that the distance between two milkw
pychu [463]

Answer:

0.004012km

Explanation:

Problem:

Conversion of millimeters(mm) to Kilometers:

value given = 4012mm

Here, we are converting from a submultiple unit to a multiple unit.

Millimeter depicts 10⁻³m and kilometer stands for 10³m

Now, we must find how many exponents will take us from 10⁻³ to  10³

careful examination shows that if we multiply a power of 10⁶ to 10⁻³ it will give a 10³:

   i.e 10⁻³ x 10⁶ = 10⁻³⁺⁶ = 10³

Therefore,

       10⁶mm = 1km

      4,012mm = \frac{4012}{1000000} = 0.004012km

4 0
3 years ago
Will mark brainliest if solved correctly.
Kamila [148]

Answer:

The answers for the questions are in the picture.

6 0
3 years ago
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How many grams of Na2SO4 should be weighed out to prepare 0.5L of a 0.100M solution?​
Nezavi [6.7K]

Answer:

7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.

Explanation:

First of all the molecular weight of Na2SO4 is 142.08 gram.Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.

    According to the given question we have to prepare 0.100 M solution

1000 ml of solution contain 142.08×0.1= 14.208 gram Na2SO4

1    ml of solution contain     14.208÷1000= 0.014 gram

0.5L or 500ml of solution contain 0.014×500= 7gram Na2SO4.

 So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.

     

3 0
3 years ago
29. Beetles undergo a complete change during their growth and development. This process
kifflom [539]

Answer:

ttfyggayxdy used to usual faith using

Explanation:

ttdrft

4 0
3 years ago
Write balanced chemical equations for the sequence of reactions that oxalic acid can undergo when it's dissolved in water.
Mashcka [7]

Answer and Explanation:

The balanced chemical equations are as follows:

The chemical formula of oxalic is  H_2C_2O_4

In the case when oxalic acts reacted with the water so here the oxalic acid eliminates one proton that leads to the development of mono acids

After that, the second step derives that when oxalic acid is in aqueous solution eliminates other proton so it represent the polyprotic acid

Now the chemical equations are as follows:

Elimination of one proton

H_2C_2O_4(aq)+H_2O(l)  \rightarrow H_2C_2O_4^-(aq) + H_3O^+(aq)

Now the elimination of other proton

HC_2O_4^-(aq)+H_2O(l)  \rightarrow C_2O_4^2^-(aq) + H_3O^+(aq)

7 0
3 years ago
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