Answer:
b
Explanation: because it says input file.read
Answer:
critical stress
= 1382.67 MPa
Explanation:
given data
plane strain fracture toughness = 54.8 MP
length of surface creak = 0.5 mm
we take here
parameter Y = 1.0
solution
we apply critical stress formula that is
critical stress
=
.............................1
here K is design stress plane strain fracture toughness and a is length of surface creak so put all these value in equation 1
critical stress
=
solve it we get
critical stress = 1382.67 MPa
As exposed stress 1030 MPa is less than critical stress 1382 MPa
so that fracture will not be occur here
Answer:
Both Technician A and technician B are correct.
Explanation: A transistor must have a P-N junction as that is where the positive and negative charges are connected.
A transistor also can be described as a semiconductor which acts as a switch and can be used to amplify currents. Transistors are very key and vital to electronic devices especially the mobile phones in recent times, it helps to ensure that electronic systems perform optimally.
The charges in the P-N junction is controlled by the availability of Positive and negative electrons.
The plastic that pollutes water ways and ocean is a symptom of mismanagement that results throughout the biosphere in both terrestrial and aquatic environment.
Explanation:
We can reduce the microplastics by filtering tap water, avoiding usage of plastic containers, usage of beauty products with microbeads, limit eating of meat and fish.
The effective solution for for reducing this problem is giving up of plastics like avoid using bottles, plastic packaging, Don't use straws instead of that paper straws can be used.
The plastics are found everywhere in the environment and now it is found in sea water, fresh water, food and drinking water.
The products that contain plastics are tyres, synthetic clothing, tennis balls, laundry, tea bags and wet wipes.
Answer:
hello the diagram attached to your question is missing attached below is the missing diagram
answer :
a) 48.11 MPa
b) - 55.55 MPa
Explanation:
First we consider the equilibrium moments about point A
∑ Ma = 0
( Fbd * 300cos30° ) + ( 24sin∅ * 450cos30° ) - ( 24cos∅ * 450sin30° ) = 0
therefore ;<em> Fbd = 36 ( cos ∅tan30° - sin∅ ) kN ----- ( 1 )</em>
A ) when ∅ = 0
Fbd = 20.7846 kN
link BD will be under tension when ∅ = 0, hence we will calculate the loading area using this equation
A = ( b - d ) t
b = 12 mm
d = 36 mm
t = 18
therefore loading area ( A ) = 432 mm^2
determine the maximum value of average normal stress in link BD using the relation below
бbd =
= 20.7846 kN / 432 mm^2 = 48.11 MPa
b) when ∅ = 90°
Fbd = -36 kN
the negativity indicate that the loading direction is in contrast to the assumed direction of loading
There is compression in link BD
next we have to calculate the loading area using this equation ;
A = b * t
b = 36mm
t = 18mm
hence loading area = 36 * 18 = 648 mm^2
determine the maximum value of average normal stress in link BD using the relation below
бbd =
= -36 kN / 648mm^2 = -55.55 MPa