Explanation:
There are two ways to find out the equivalent impulse response of the system.
1. Convolution in time domain
2. Simple multiplication in Laplace domain
2nd method is efficient, easy and is less time consuming.
Step 1: Take the Laplace transform of the given three impulse response functions to convert time domain signals into s-domain
Step 2: Once we get signals in s-domain, multiply them algebraically to get the equivalent s-domain response.
Step 3: Take inverse Laplace transform of the equivalent impulse response to convert from s-domain into time domain.
Solution using Matlab:
Step 1: Take Laplace Transform
Ys1 = 1/(s + 1)
Ys2 = 1/s - exp(-s/2)/s
Ys3 = exp(-3*s)
Step 2: Multiplication in s-domain
Y = (exp(-(7*s)/2)*(exp(s/2) - 1))/(s*(s + 1))
Step 3: Inverse Laplace Transform (Final Solution in Time Domain)
h = heaviside(t - 7/2)*(exp(7/2 - t) - 1) - heaviside(t - 3)*(exp(3 - t) - 1)
Answer:
Given:
high temperature reservoir
low temperature reservoir
thermal efficiency
The engines are said to operate on Carnot cycle which is totally reversible.
To find the intermediate temperature between the two engines, The thermal efficiency of the first heat engine can be defined as
The thermal efficiency of second heat engine can be written as
The temperature of intermediate reservoir can be defined as
Answer:
Rate of heat transfer to river=1200MW
So the actual amount of heat rejected ti the river will be less as there will some heat loss to surrounding and in pipes
Explanation:
In order to find the actual heat transfer rate is lower or higher than its value we will first find the rate of heat transfer to power plant:
From First law of thermodynamics:
Rate of heat transfer to river=heat transfer to power plant-work done
Rate of heat transfer to river=2000-800
Rate of heat transfer to river=1200MW
So the actual amount of heat rejected ti the river will be less as there will some heat loss to surrounding and in pipes.