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NeTakaya
3 years ago
15

Fractional distillation of a mass mixture of 10 g water and 10 g perchloric acid would yield a distillate with what composition

of water and nitric acid?
Chemistry
1 answer:
jek_recluse [69]3 years ago
8 0

Azeotrope is a mixture of two or more liquids whose proportions cannot be changed by simple distillation.

Explanation:

Nitic acid and water is an example of azeotrope. The composition of 68% of nitric acid and 32% of water by mass in a boiling point of 393.5k.

The composition of perchloric acid (71.6%) and water boils at 203°c. Pure iron solution weights about 10g is placed in a beaker, hydrochloric acid and nitric acid mixtures are added and heated to dissolve. Add perchloric acid until it evaporate and produces white smoke.cool it down add water and dissolve the salt.

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How many atoms are in 123 g of calcium
Keith_Richards [23]

Answer:

Molar mass of Ca = 40 g / mol , given 123 g Ca is 123/40= 3.075 moles,

1 mole = 6.022 * 10^23 atoms, so 3.075 moles Ca= 18.51*10^23 atoms

Explanation:

5 0
2 years ago
The molar heat of vaporization of water is 40.7kJ/mol. How much heat must be absorbed to convert 50.0 grams of liquid water at 1
EleoNora [17]
During a phase change the temperature does not change since all of the heat is being absorbed in order to break the intermolecular forces.  Due to that, the formula will not need to have T in it and is actually q=nΔH(v).
n=the number of moles (in this case 2.778mol of water since you divide 50g by 18g/mol).
ΔH(v)=the molar heat of vaporization (in this case 40.7kJ/mol).
q=the heat that must be absorbed
q=2.778mol×40.7kJ/mol
q=113.1kJ
Therefore the water needs to absorb 1.13×10²kJ.

I hope this helps.  Let me know if anything is unclear.

4 0
3 years ago
The equilibrium concentrations of the reactants and products are [HA]=0.280 M, [H+]=4.00×10−4 M, and [A−]=4.00×10−4 M. Calculate
Tems11 [23]

Answer:

6.24

Explanation:

The following data were obtained from the question:

Concentration of HA, [HA] = 0.280 M,

Concentration of H+, [H+] = 4×10¯⁴ M

Concentration of A-, [A−] = 4×10¯⁴ M

pKa =.?

Next, we shall write the balanced equation for the reaction. This is given below:

HA <===> H+ + A-

Next, we shall determine the equilibrium constant Ka for the reaction. This can be obtained as follow:

Equilibrium constant for a reaction is simply the ratio of concentration of the product raised to their coefficient to the concentration of the reactant raised to their coefficient.

The equilibrium constant for the above equation is given below:

Ka = [H+] [A−] /[HA]

Concentration of HA, [HA] = 0.280 M,

Concentration of H+, [H+] = 4×10¯⁴ M

Concentration of A-, [A−] = 4×10¯⁴ M

Equilibrium constant (Ka) =

Ka = (4×10¯⁴ × 4×10¯⁴) / 0.280

Ka = 1.6×10¯⁷/ 0.280

Ka = 5.71×10¯⁷

Therefore, the equilibrium constant for the reaction is 5.71×10¯⁷

Finally, we shall determine the pka for the reaction as follow:

Equilibrium constant, Ka = 5.71×10¯⁷

pKa =?

pKa = – Log Ka

pKa = – Log 5.71×10¯⁷

pKa = 6.24

Therefore, the pka for the reaction is 6.24.

6 0
3 years ago
6. What is a polyatomic ion? (You should also memorize the name, formula, and charge of the polyatomic ions listed in the lectur
strojnjashka [21]
A polyatomic ion is a group of elements that has a charge that is not 0. for example the charge of P04 is -3 
6 0
3 years ago
Which of these statements best describes the relationship between elements, compounds, and pure substances?
olchik [2.2K]

pure substances can be divided into two groups; elements and compounds

5 0
2 years ago
Read 2 more answers
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