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Tpy6a [65]
3 years ago
6

A group of Advanced Open Water Divers plans to make two dives. The first dive is on a reef in 90 feet of water for 20 minutes. T

he group then remains on the surface for 1 hour. The second dive is on a wreck in 60 feet of water, with a planned bottom time of 30 minutes. What will be the ending pressure group after the second dive
Physics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

The ending pressure is R.

Explanation:

This is Recreational scuba diving (R). According to standards, this diving has prescribed depth limit of 130 ft. This means that the limit must include a depth that is not greater than 130 ft while using only compressed air and not even requiring a decompression stop.

Now, from the question, we can see that that there was a prescribed limit of 60ft of water with a planned bottom time of 30 minutes.

Thus, the ending pressure is R.

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You place a 0.17 kg can of soup and a 0.31 kg jar of pickles on the kitchen counter, separated by a distance of 0.42 m. What is
tangare [24]

1.984 \times 10^{-11} \mathrm{N} \text { is the force of gravity exerted on the jar of pickles. }

<u>Explanation</u>:

According to Newton's third law that each force has an equal and opposite reaction force in this case both of the jars will exert the same force an each other

. The force is given by

\mathrm{F}=\frac{G \times M_{1} \times M_{2}}{r^{2}}

Where, F = force, G=\text { gravitational constant }=\left(6.67 \times 10^{-11}\right), mass \left(\mathrm{M}_{1}\right)=0.17 \mathrm{kg}, mass \left M_{2}= 0.31 \mathrm{kg} and Distance(r) = 0.42 m.

Substitute the values in the formula.

\mathrm{F}=\frac{6.67 \times 10^{-11} \times 0.17 \times 0.31}{0.42^{2}}

\mathrm{F}=\frac{3.51 \times 10^{-12}}{0.176}

\mathrm{F}=1.984 \times 10^{-11} \mathrm{N}

\text { The force of gravity exerted on the jar of pickles is } 1.984 \times 10^{-11} \mathrm{N} \text { . }

3 0
3 years ago
A simple pendulum is made from a 0.54-m-long string and a small ball attached to its free end. The ball is pulled to one side th
Serga [27]

Answer:

0.37sec

Explanation:

Period of oscillation of a simple pendulum of length L is:

T = 2 π × √ (L /g)

L=length of string 0.54m

g=acceleration due to gravity

T-period

T = 2 x 3.14 x √[0.54/9.8]

T = 1.47sec

An oscillating pendulum, or anything else in nature that involves "simple harmonic" (sinusoidal) motion, spends 1/4 of its period going from zero speed to maximum speed, and another 1/4 going from maximum speed to zero speed again, etc. After four quarter-periods it is back where it started.

The ball will first have V(max) at T/4,

=>V(max) = 1.47/4 = 0.37 sec

3 0
3 years ago
HURRY I NEED IT NOW What is the density at 20oC of 12.0 milliliters of a liquid that has a mass of 4.05 grams?
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Density is the mass per unit volume of any object. It is calculated by dividing the mass of an object by its volume. This is:

ρ = m/V

ρ = 4.05 g  / 12 mL

ρ = 0.3375 g/mL

<h3>ρ ≅ 0.338 g/mL</h3>

OPTION A

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A car traveled 1,215 km West from El Paso to Dallas in 13.5 hours. What was its velocity?
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............The answer is B
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You discover a binary star system in which one member is a 15 solar mass main-sequence star and the other star is a 10 solar mas
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Answer:

A star with 15 solar masses is too big to be a main-sequence star.

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